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NotesMath AI HLTopic 1.3Sum to Infinity
Back to Math AI HL Topics
1.3.48 min read

Sum to Infinity (Math AI HL)

IB Mathematics: Applications and Interpretation · Unit 1

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Contents

  1. 1When does S∞ exist? The |r| < 1 rule
  2. 2Using the S∞ formula
  3. 3IB Exam-Style Worked Example — Saving with Halving Amounts
The big idea: A geometric series goes on forever. But sometimes, all those infinite terms add up to a finite number.

The answer depends on one thing: is each term getting smaller and smaller toward zero?

The rule

Common ratio rWhat happens to the terms?Does S∞ exist?
r = 2 (e.g. 2, 4, 8, 16, ...)Terms grow bigger and biggerNo
r = 1 (e.g. 5, 5, 5, 5, ...)Terms stay the same foreverNo
r = −1 (e.g. 3, −3, 3, −3, ...)Terms flip sign, never shrinkNo
r = 0.5 (e.g. 8, 4, 2, 1, ...)Terms shrink toward zeroYes
r = −0.5 (e.g. 8, −4, 2, −1, ...)Terms shrink in size (ignore sign)Yes
The S∞ condition: S∞ exists only when |r| < 1

|r| means the size of r, ignoring any negative sign. So r = −0.7 → |r| = 0.7 → |r| < 1

If |r| ≥ 1 → write "S∞ does not exist". Never calculate it. You will lose marks if you do.

Practice: does S∞ exist?

Series: 3 + 6 + 12 + 24 + ...

r = 6 ÷ 3 = 2 → |r| = 2 ≥ 1

S∞ does not exist. The terms keep growing.

Series: 10 + 5 + 2.5 + 1.25 + ...

r = 5 ÷ 10 = 0.5 → |r| = 0.5 < 1

S∞ exists.

Series: 6 − 4 + 8/3 − 16/9 + ...

r = −4 ÷ 6 = −2/3 → |r| = 2/3 < 1

S∞ exists. Negative r is fine as long as |r| < 1.

Series: 5 + 5 + 5 + 5 + ...

r = 5 ÷ 5 = 1 → |r| = 1 → NOT less than 1

S∞ does not exist. The terms never shrink.

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The formula: Once you confirm |r| < 1, use:

S∞ = u₁ ÷ (1 − r)

You always need two things: the first term u₁, and the common ratio r.
How to remember this (not on the formula sheet): S∞ is not given in the IB formula booklet — only Sₙ is. But you can build it from the formula you do have on your sheet.

You are not memorising a new formula — you are crossing out rⁿ from the one already on your sheet.

Build S∞ from Sₙ

1

Start with Sₙ

On your sheet: Sₙ = u₁(1 − rⁿ) ÷ (1 − r)

2

Let rⁿ go to 0

When |r| < 1, rⁿ shrinks to zero as n → ∞. So just replace rⁿ with 0.

3

Simplify

S∞ = u₁(1 − 0) ÷ (1 − r) = u₁ ÷ (1 − r)

Sₙ → cross out rⁿ → S∞

Type 1 — Find S∞ from a sequence

The sequence 8, 4, 2, 1, ... goes on forever.

Does S∞ exist?

If so, find it.

Step by step

  1. Find r: r = 4 ÷ 8 = 0.5
  2. Check: |0.5| < 1 — S∞ exists
  3. Write the formula: S∞ = u₁ ÷ (1 − r)
  4. Substitute: S∞ = 8 ÷ (1 − 0.5) = 8 ÷ 0.5
  5. S∞ = 16

Final answer

S∞ = 16

Type 2 — Find u₁ given S∞ and r

A geometric series has r = 0.4 and S∞ = 25.

Find the first term u₁.

Step by step

  1. Check: |0.4| < 1 (we're told S∞ = 25, so it already exists)
  2. Write the formula: S∞ = u₁ ÷ (1 − r)
  3. Substitute: 25 = u₁ ÷ (1 − 0.4)
  4. Simplify the bracket: 25 = u₁ ÷ 0.6
  5. Multiply both sides by 0.6: u₁ = 25 × 0.6
  6. u₁ = 15

Final answer

u₁ = 15

Type 3 — Find r given S∞ and u₁

A geometric series has u₁ = 12 and S∞ = 20.

Find r.

Step by step

  1. Write the formula: S∞ = u₁ ÷ (1 − r)
  2. Substitute: 20 = 12 ÷ (1 − r)
  3. Rearrange: 1 − r = 12 ÷ 20 = 0.6
  4. r = 1 − 0.6
  5. r = 0.4

Final answer

r = 0.4

Rearranging the formula: The formula S∞ = u₁ ÷ (1 − r) has three variables.

If you know any two, you can always find the third:

- Find S∞: substitute u₁ and r directly - Find u₁: multiply both sides by (1 − r) - Find r: substitute S∞ and u₁, then solve 1 − r = u₁ ÷ S∞

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Two ideas, one question: IB questions on this topic often come in two parts. One part uses S∞, the other uses Sₙ.

'Will it ever reach the target?' → S∞

  • Calculate S∞ and compare it to the target.
  • If S∞ < target, it can never get there.
  • Signal: 'never reach' / 'cannot reach'

'Reach the target after n steps?' → Sₙ

  • Set Sₙ = target and solve for the first deposit.
  • Signal: 'after n years / weeks / steps'
Practice Question — 6 marks: Leila is saving money for a new laptop. At the start of each week, she puts money into a savings tin. In the first week she deposits $6 000. Each week after that, she adds exactly half the amount she deposited the week before.

Answer both parts

  • (a) Show that Leila will never reach her savings target of $15 000, no matter how many weeks pass. [3 marks]
  • (b) Leila wants to reach exactly $15 000 after 4 weeks of saving. Find the minimum amount she needs to deposit in the first week. Give your answer to the nearest dollar. [3 marks]

Part (a) — Show it never reaches the target

If the first deposit is 6 000 and r = 0.5, show that the total saved can never reach $15 000.

Step by step

  1. Identify the structure: each week adds half of the previous week — this is a geometric series
  2. Common ratio: r = 0.5 (each term is half the previous one)
  3. Check: |0.5| < 1 — S∞ exists
  4. Maximum possible total (saving forever): S∞ = first deposit ÷ (1 − r)
  5. Substitute: S∞ = 6000 ÷ (1 − 0.5) = 6000 ÷ 0.5
  6. S∞ = 12 000
  7. Since 12 000 < 15 000, even saving forever will not reach the target
  8. Therefore, Leila will never reach $15 000.

Final answer

S∞ = 12 000 < 15 000 — target is never reached.

What 'Show that...' means: The answer is printed in the question — your job is to prove it. You need three things.

Most students stop at step 1. That loses a mark.

Three things to write

1

Calculate

Calculate S∞ and write the number: S∞ = 12 000

2

Compare

Compare it to the target: 12 000 < 15 000

3

Conclude

Write a conclusion in words: 'Even saving forever, Leila cannot reach $15 000.'

Calculate → compare → conclude

Part (b) — Find the minimum initial deposit

Find the first deposit so that the total saved after exactly 4 weeks equals $15 000.

Step by step

  1. This is a finite sum — we are saving for exactly 4 weeks, not forever
  2. Use the Sₙ formula: Sₙ = first deposit × (1 − rⁿ) ÷ (1 − r)
  3. Set S₄ = 15 000 with r = 0.5 and n = 4
  4. 15 000 = first deposit × (1 − 0.5⁴) ÷ (1 − 0.5)
  5. 15 000 = first deposit × (1 − 0.0625) ÷ 0.5
  6. 15 000 = first deposit × 0.9375 ÷ 0.5
  7. 15 000 = first deposit × 1.875
  8. first deposit = 15 000 ÷ 1.875
  9. first deposit = 8 000

Final answer

Minimum initial deposit = $8 000

Two questions, two different formulas: IB questions on this topic often come in two parts — back to back. The signal words tell you which formula each part needs.
QuestionFormulaWhat to doSignal words
'Will it ever reach the target?'S∞Calculate S∞. If S∞ < target, it can never get there.never reach / cannot reach
'Reach the target after n steps?'SₙSet Sₙ = target and solve for the first deposit.after n years / weeks / steps

Part (a) — Show it never reaches the target

  • Write r = 0.5 in your working — this one step earns a mark on its own
  • Use the S∞ formula and write the result (S∞ = 12 000)
  • Write the comparison: 12 000 < 15 000
  • Write a conclusion sentence: 'Even saving forever, Leila cannot reach $15 000.'
The number alone is not enough: Leaving out the comparison or conclusion sentence loses a mark — the number alone is not enough.

Part (b) — Find the first deposit

  • Write the equation with the total set equal to 15 000 — this earns a mark even before you solve it
  • Show the unrounded answer
  • Give the final answer rounded to the nearest dollar
What to write to score full marks: On both parts: always write the equation or formula before your calculator answer. A correct number with no working shown does not score full marks.

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A geometric series has first term 6 and common ratio 1/3. Find S∞. [2 marks]

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