Back to Topic 5.13 — Kinematics (HL only)
5.13.1Math AI HL8 flashcards

Kinematics with calculus

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Card 1 of 85.13.1
5.13.1
Question

How do you get velocity and acceleration from position s(t)?

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All 8 Flashcards — Kinematics with calculus

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Card 1formula

Question

How do you get velocity and acceleration from position s(t)?

Answer

Differentiate: v = ds/dt (first derivative) and a = dv/dt = d²s/dt² (second derivative).

Card 2formula

Question

How do you get velocity and position from acceleration a(t)?

Answer

Integrate: v = ∫a dt and s = ∫v dt — each integration adds a + C found from an initial condition (e.g. v(0), s(0)).

Card 3concept

Question

What does 'instantaneously at rest' mean?

Answer

The velocity is zero: solve v = 0. The particle changes direction only where v actually changes sign.

Card 4concept

Question

What is the difference between displacement and distance travelled?

Answer

Displacement = ∫v dt (signed net change in position); distance travelled = ∫|v| dt (total path length, always ≥ 0).

Card 5concept

Question

How do you find total distance travelled by hand?

Answer

Find where v = 0, split the integral at those times, integrate each piece, then add the MAGNITUDES (or integrate |v| on the GDC).

Card 6concept

Question

How do you find the greatest velocity in the interior of an interval?

Answer

Solve a = 0 (where dv/dt = 0, velocity is at a max/min), then also check the endpoints of the interval.

Card 7concept

Question

Why does each integration in kinematics need a + C?

Answer

Integration only recovers the shape; the + C is the unknown starting value, fixed by an initial condition such as v(0) or s(0).

Card 8concept

Question

A cyclist has v(t) = t² − 6t + 8 on 0 ≤ t ≤ 5. Displacement vs distance?

Answer

Displacement = ∫₀⁵ v dt = 20/3 ≈ 6.67 m; distance = ∫|v| dt (split at t = 2, 4) = 28/3 ≈ 9.33 m.

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IB Math AI Kinematics with calculus Flashcards | 5.13.1 | Aimnova | Aimnova