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NotesMath AATopic 4.4
Unit 4 · Statistics & Probability · Topic 4.4

IB Math AA — Correlation & regression

Topic 4.4 of IB Mathematics: Analysis and Approaches covers Correlation & regression, which is part of Unit 4: Statistics & Probability. Students explore key concepts including Scatter & correlation, Regression line. A strong understanding of correlation & regression is essential for IB Math AA exams and builds the foundation for connected topics across the syllabus.

Exam technique guidePractice questions

Key concepts in Correlation & regression

Key Idea: This topic is about measuring and modelling how two variables move together — describing a scatter, putting a number on it with r, and fitting the line y = ax + b to predict. On Paper 2 the GDC hands you a, b and r in one step.

📈 Describing a scatter & Pearson's r

Describe a scatter by its direction and its strength. Direction — positive (both rise together) or negative (one rises as the other falls). Strength — strong (points hug a line) or weak (loosely scattered). e.g. 'strong positive', 'weak negative'. r puts a number on exactly this.
−1≤r≤1-1 \le r \le 1−1≤r≤1
sign of r\text{sign of } rsign of r
the direction — + is positive, − is negative
∣r∣|r|∣r∣
the strength — near 1 is strong, near 0 is weak
r=±1r = \pm 1r=±1
the points lie exactly on a straight line
Value of rDescription
r = 0.93Strong positive (close to +1)
r = 0.45Weak/moderate positive
r = −0.21Weak negative (close to 0)
r = −0.98Strong negative (close to −1)
r = 0No linear correlation

📉 The regression line y = ax + b

y=ax+by = ax + by=ax+b
aaa
gradient — change in y per 1-unit rise in x
bbb
y-intercept — predicted y when x = 0
The regression line always passes through (x̄, ȳ). So substituting the means into y = ax + b works exactly — handy for finding a missing mean, or for checking your line. To predict y use y on x; to predict x use x on y. The two lines cross at (x̄, ȳ), so solving them together gives the means.

✏️ IB-style worked examples

IB-style question — describe correlation from r

A study of weekly rainfall and umbrella sales gives r = 0.91, and a study of outdoor temperature and heater use gives r = −0.87. Describe the correlation in each case.

Step by step:

  1. Read r in two parts: sign = direction, |r| close to 1 = strength.

    r=0.91⇒+, ∣r∣≈1r = 0.91 \Rightarrow +,\ |r| \approx 1r=0.91⇒+, ∣r∣≈1
  2. Do the same for the second value.

    r=−0.87⇒−, ∣r∣≈1r = -0.87 \Rightarrow -,\ |r| \approx 1r=−0.87⇒−, ∣r∣≈1
Final answer:

r = 0.91 → strong positive; r = −0.87 → strong negative.

IB-style question — find r and the regression line (Paper 2)

For six bakeries, x = number of staff and y = loaves baked per hour are (2, 18), (3, 26), (4, 31), (5, 40), (6, 44), (7, 53). Find r and the regression line of y on x, then predict y when x = 8.

Step by step:

  1. Enter the pairs in L1, L2 and run linear regression on the GDC.

    r≈0.996,a=6.8, b≈4.73r \approx 0.996,\quad a = 6.8,\ b \approx 4.73r≈0.996,a=6.8, b≈4.73
  2. Write the line, then substitute x = 8 to predict.

    y=6.8x+4.73y = 6.8x + 4.73y=6.8x+4.73
  3. x = 8 is just outside the data — flag it as extrapolation.

    y≈6.8(8)+4.73=59.1y \approx 6.8(8) + 4.73 = 59.1y≈6.8(8)+4.73=59.1
Final answer:

r ≈ 0.996 (very strong positive); y = 6.8x + 4.73; y ≈ 59 loaves at x = 8.

IB-style question — interpret and use the line

A regression line for a seedling's height y cm against age x weeks is y = 1.8x + 4, and the mean age is x̄ = 5. Interpret a and b, and find the mean height ȳ.

Step by step:

  1. Gradient a = growth per week; intercept b = height at week 0.

    a=1.8 cm/week,b=4 cm at x=0a = 1.8\ \text{cm/week},\quad b = 4\ \text{cm at } x=0a=1.8 cm/week,b=4 cm at x=0
  2. The mean point (x̄, ȳ) lies on the line — substitute x̄ = 5.

    yˉ=1.8(5)+4=13\bar{y} = 1.8(5) + 4 = 13yˉ​=1.8(5)+4=13
Final answer:

Grows ≈ 1.8 cm per week, ≈ 4 cm at week 0; ȳ = 13 cm.

🔒 GDC walkthrough

Step through the exact calculator keystrokes, screen by screen, in study mode.

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Important: A strong r shows the variables move together, NOT that one causes the other — never claim cause from r alone. Two more traps: r only measures a linear pattern (a strong curve can give a small r), and extrapolating far beyond the data is unreliable — only trust predictions inside the data range.

Tap each card to reveal the answer.

What does r = −0.95 tell you? Strong negative linear correlation — sign is −, |r| is close to 1.

The range of Pearson's r −1 ≤ r ≤ 1 — sign = direction, |r| near 1 = strong, near 0 = weak.

In y = ax + b, what is a? The gradient — the change in y for each 1-unit increase in x.

Which point is the line guaranteed to pass through? The mean point (x̄, ȳ) — both regression lines cross there.

Predict x from a known y — which line? The line of x on y (use y on x only to predict y).

r = 0.99 between ice-cream sales and drownings — cause? No — correlation ≠ causation; a third factor (hot weather) drives both.

Exam Tips

  • Describe a scatter with BOTH a direction and a strength.
  • r's sign is the direction; how close |r| is to 1 is the strength; −1 ≤ r ≤ 1.
  • On Paper 2, get a, b and r from LinReg(ax+b) — never compute by hand.
  • The regression line always passes through (x̄, ȳ); predict y with y on x.
  • A strong r is not proof of cause, and extrapolating beyond the data is unreliable.

What you'll learn in Topic 4.4

  • 4.4.1 Scatter & correlation
  • 4.4.2 Regression line
Suggested study order: Read the notes for each sub-topic below → test yourself with flashcards → attempt practice questions → review exam technique.

Study resources — 4.4 Correlation & regression

4.4.1

Scatter & correlation

Notes
4.4.2

Regression line

Notes

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Topic 4.4 Correlation & regression forms a core part of Unit 4: Statistics & Probability in IB Math AA. Mastering these concepts will strengthen your understanding of connected topics across the syllabus and prepare you for exam questions that require analysis, evaluation, and real-world application.

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