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NotesMath AATopic 3.3
Unit 3 · Geometry & Trigonometry · Topic 3.3

IB Math AA — Bearings & elevation

Topic 3.3 of IB Mathematics: Analysis and Approaches covers Bearings & elevation, which is part of Unit 3: Geometry & Trigonometry. Students explore key concepts including Elevation & depression, Bearings. A strong understanding of bearings & elevation is essential for IB Math AA exams and builds the foundation for connected topics across the syllabus.

Exam technique guidePractice questions

Key concepts in Bearings & elevation

Key Idea: This topic turns a word problem about heights, distances and directions into a triangle you can solve. The exam pattern is always the same: read → draw the diagram → pick the rule (right-angled trig, or the sine/cosine rule).

📐 Elevation, depression & bearings

TermWhat it isWatch for
Angle of elevationMeasured up from the horizontal to a point above youFrom the horizontal, not the vertical
Angle of depressionMeasured down from the horizontal to a point below you= the elevation back up (alternate angles)
Three-figure bearingAngle measured clockwise from North, 3 digits5° is 005°; sweep clockwise, never anticlockwise
N = 000°, E = 090°, S = 180°, W = 270°. A direction like N40°E = 040°; S30°W = 180° + 30° = 210°; South-East = 135°. Back bearing = ±180° (A from B given B from A): add 180° if it's under 180°, subtract if it's 180° or more. Keep it between 000° and 360°.

🔺 Which rule? (Paper 1 by-hand, Paper 2 with GDC)

The triangle is…UseWhen
Right-angledSOH-CAH-TOA (usually tan)One angle + one side; height vs. ground distance
Non-right, 2 sides + included angleCosine rule for the third sideTwo journey legs on different bearings
Non-right, 3 sides (angle wanted)Cosine rule rearranged for the angleAll three distances known
Non-right, side + its opposite angleSine ruleAn angle and the side facing it are paired

✏️ IB-style worked examples

IB-style question — elevation, find a height

From a point 65 m from the base of a tower, the angle of elevation to the top is 38°. Find the height of the tower.

Step by step:

  1. Height is opposite, 65 m is adjacent → use tan.

    tan⁡38∘=h65\tan 38^\circ = \frac{h}{65}tan38∘=65h​
  2. Solve for the height.

    h=65tan⁡38∘≈50.8 mh = 65\tan 38^\circ \approx 50.8\text{ m}h=65tan38∘≈50.8 m
Final answer:

About 50.8 m. (Add eye height if the angle is taken from a person's eye.)

IB-style question — depression, find a distance

From the top of a 55 m cliff, the angle of depression to a buoy is 24°. Find the buoy's distance from the base of the cliff.

Step by step:

  1. Depression (24°) equals the elevation from the buoy, so it sits inside the triangle.

    tan⁡24∘=55d\tan 24^\circ = \frac{55}{d}tan24∘=d55​
  2. Rearrange for the distance.

    d=55tan⁡24∘≈124 md = \frac{55}{\tan 24^\circ} \approx 124\text{ m}d=tan24∘55​≈124 m
Final answer:

About 124 m.

IB-style question — two observers, cosine rule for an angle

An object is seen from two points. The slant distances to it are 120 m and 150 m, and the two points are 90 m apart. Find the angle at the object.

Step by step:

  1. Three sides, angle wanted → cosine rule rearranged.

    cos⁡θ=1202+1502−9022(120)(150)\cos\theta = \frac{120^2 + 150^2 - 90^2}{2(120)(150)}cosθ=2(120)(150)1202+1502−902​
  2. Evaluate, then inverse-cosine.

    cos⁡θ=2880036000⇒θ≈36.9∘\cos\theta = \frac{28800}{36000} \Rightarrow \theta \approx 36.9^\circcosθ=3600028800​⇒θ≈36.9∘
Final answer:

About 36.9°.

IB-style question — bearing of one place, then its back bearing

A direction is given as 'North-West'. (a) Write it as a three-figure bearing. (b) If the bearing of B from A is 050°, find the bearing of A from B.

Step by step:

  1. (a) NW is 45° west of North (000°) — that is 45° back from a full turn of 360°.

    360∘−45∘=315∘360^\circ - 45^\circ = 315^\circ360∘−45∘=315∘
  2. (b) 050° is under 180°, so add 180° for the back bearing.

    050∘+180∘=230∘050^\circ + 180^\circ = 230^\circ050∘+180∘=230∘
Final answer:

(a) 315°. (b) 230°.

IB-style question — journey on two bearings, cosine rule

A ship sails 9 km on a bearing of 050°, then 6 km on a bearing of 110°. Find its direct distance from the start.

Step by step:

  1. Interior angle at the turn, from the North lines: 180° − (110° − 50°).

    ∠=180∘−60∘=120∘\angle = 180^\circ - 60^\circ = 120^\circ∠=180∘−60∘=120∘
  2. Two legs + included angle → cosine rule.

    d2=92+62−2(9)(6)cos⁡120∘=171d^2 = 9^2 + 6^2 - 2(9)(6)\cos 120^\circ = 171d2=92+62−2(9)(6)cos120∘=171
  3. Square-root for the distance.

    d=171≈13.1 kmd = \sqrt{171} \approx 13.1\text{ km}d=171​≈13.1 km
Final answer:

About 13.1 km.


Important: Bearings are measured clockwise from North, always with three digits. Sketch the North arrow first and sweep clockwise — never anticlockwise, never from South, never from the East line. A bearing drawn the wrong way sends every later angle and side astray.

Tap each card to reveal the answer.

Elevation vs. depression — measured from what? Both from the horizontal — up = elevation, down = depression (never the vertical).

Angle of depression to a boat is 18° — what's the elevation from the boat? 18° — depression equals the elevation back (alternate angles).

Write the direction 'due West' as a bearing 270° — three-quarters of a turn clockwise from North.

Bearing of Y from X is 200° — bearing of X from Y? 020° — it's 180° or more, so subtract 180°.

Two legs of 7 km and 4 km with a 60° turn between — which rule? Cosine rule — two sides and the included (interior) angle.

Write the bearing for an angle of 7° clockwise from North 007° — bearings always use three digits.

Exam Tips

  • Always: read → draw the diagram → choose the rule. The sketch is where the marks start.
  • Bearings go clockwise from North and use three digits — 5° is 005°.
  • Depression equals the elevation back up; mark that equal angle inside your triangle.
  • Right-angled → SOH-CAH-TOA (often tan). Non-right → sine or cosine rule.
  • For journeys, find the interior angle at the turn from the North lines — it's rarely just the difference of the two bearings.

What you'll learn in Topic 3.3

  • 3.3.1 Elevation & depression
  • 3.3.2 Bearings
Suggested study order: Read the notes for each sub-topic below → test yourself with flashcards → attempt practice questions → review exam technique.

Study resources — 3.3 Bearings & elevation

3.3.1

Elevation & depression

Notes
3.3.2

Bearings

Notes

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Topic 3.3 Bearings & elevation forms a core part of Unit 3: Geometry & Trigonometry in IB Math AA. Mastering these concepts will strengthen your understanding of connected topics across the syllabus and prepare you for exam questions that require analysis, evaluation, and real-world application.

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