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NotesMath AATopic 4.6Conditional probability
Back to Math AA Topics
4.6.57 min read

Conditional probability

IB Mathematics: Analysis and Approaches · Unit 4

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Contents

  1. 1Given the weather: read a branch
  2. 2Given a win: which die roll?
  3. 3Conditional probability from a table
  4. 4Conditional probability from a Venn diagram
  5. 5False alarms: when a result is wrong

Given the weather: read the right branch

Question: the bus on a rainy day: There is a 30% chance of rain.

On rainy days, the bus has a 25% chance of being late.

Today, you know it is raining. What is the probability that the bus will be late?
Given rain, restrict attention to the Rain branch. The Rain to Late branch is 0.25, so the conditional probability is 25%. The No rain group is ignored.
The question already tells you the weather. Read the bus chance from that branch.
Answer: 25%: We look only at rainy days. The question tells us that the bus is late on 25% of those days.

So P(late | rain) = 0.25. The symbol | means “given that”.

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We know she won. Did she roll a 6?

The game: roll first, then spin: Mia rolls a fair six-sided die.

• If she rolls a 6, she uses spinner X. It has a 1/2 chance of winning.

• If she rolls 1, 2, 3, 4 or 5, she uses spinner Y. It has a 1/5 chance of winning.
Question: Mia has won: You know Mia won, but you did not see her die roll.

What is the probability that she rolled a 6?

Look only at the winning games. What fraction of those started with a 6?
Two winning paths: rolling a 6 and winning has probability 1/12; rolling 1 to 5 and winning has probability 2/12. Among all wins, the roll-6 share is 1/3.
We know the result: Mia won. Look only at the winning paths.
Answer: 1/3, about 33.3%: Win after a 6: 1/6 × 1/2 = 1/12.

All wins: 1/12 + 2/12 = 3/12.

So P(rolled a 6 | won) = (1/12) ÷ (3/12) = 1/3.

The | means “given that”. We divide by the chance of all wins, because we already know she won.
Which games do we count?: We already know Mia won, so ignore every game she lost.

She could have won after rolling a 6, or after rolling 1–5. Count both kinds of win in the total.

Answer = chance of “roll a 6 AND win” ÷ chance of any win.

Here that is (1/12) ÷ (3/12) = 1/3. So one third of the winning games started with a 6.

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Conditional probability from a table

Question: under-18 phone users: A phone shop surveys 200 customers, as shown in the table.

A customer is chosen at random. You are told they are under 18.

What is the probability that they use an iPhone?
Phone-use table. Among the 60 under-18 customers, 26 use iPhones. Given under 18, probability is 26/60.
Given under 18 → use that row only → 26 out of 60.
Answer: 26/60 ≈ 0.433: Look only at the under-18 row: 60 customers, including 26 iPhone users.

So the probability is 26 ÷ 60 ≈ 0.433, or 43.3%.

Music and Drama: how many do both?

Question: 8 students are in the Music club only.

60% of the Music club also do Drama.

How many students do both Music and Drama?
Music and Drama Venn: 60% of Music students do both. The other 40% are 8 Music-only students. The whole Music club has 20 students, so 12 do both.
8 students are 40% of the Music club. Find the whole group, then subtract those 8.

Answer: 12 students

How many do both?

Step by step

  1. If 60% do both, the remaining 40% do Music only. These are the 8 students.
  2. Find the whole Music group: 40% = 0.4.
  3. Remove the 8 Music-only students.

Final answer

12 students do both Music and Drama.

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The alarm rings — is there really smoke?

Picture a smoke alarm: A smoke alarm is meant to ring when there is smoke.

Sometimes it rings even though there is no smoke. That is a false alarm.
Information: 100 practice checks: A school carries out 100 practice checks on an alarm.

20 checks have smoke: the alarm rings in 18 of them.

80 checks have no smoke: the alarm still rings in 8 of them.
Question: One check is chosen at random.

You are told the alarm rang.

What is the probability that there was smoke?
Count tree of 100 alarm checks: 20 with smoke give 18 rings and 2 quiet checks; 80 without smoke give 8 false alarms and 72 quiet checks. Given a ring, 18 of the 26 ringing checks had smoke: 18/26 = 9/13, about 69.2%.
Count first: of the 26 ringing checks, 18 had smoke.
What was really there?Alarm ringsAlarm stays quietTotal
Smoke18220
No smoke87280
Total2674100
The exam words, using this alarm: Positive means the alarm rings. Negative means it stays quiet.

False positive: it rings with no smoke — the 8 false alarms.

False negative: it stays quiet with smoke present — the 2 missed warnings.

Incorrect results: both mistakes together, so 8 + 2 = 10 out of 100, or 10%.

If the question asks for an expected number

The chance of an incorrect result is 10%. Find the expected number of incorrect results in 1000 similar checks.

Solution

  1. Multiply the number of checks by the probability of a mistake.

Final answer

100 incorrect results are expected.

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Related Math AA Topics

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