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NotesMath AATopic 1.9Pascal's triangle & nCr
Back to Math AA Topics
1.9.15 min read

Pascal's triangle & nCr

IB Mathematics: Analysis and Approaches · Unit 1

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Contents

  1. 1Pascal's triangle
  2. 2The nCr formula & the GDC
  3. 3The binomial theorem
  4. 4Exam-style question
The big idea: The coefficients of (a + b)ⁿ are row n of Pascal's triangle — start each row with 1, and every inside number is the sum of the two above it.

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Small n only: Pascal's triangle is quickest for small n (up to about 6).

For a bigger power, use nCr (next section) instead of writing out every row.

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Coefficients without the triangle: For bigger powers, a coefficient is a combination nCr — compute it with the formula, or with the GDC's nCr button.

First — what the ! sign means

  • n! (say "n factorial") means multiply n by every whole number below it, down to 1 — e.g. 4! = 4 × 3 × 2 × 1 = 24.

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the total you're choosing from
how many you choose from it

IB-style question — a bigger one

Find ¹⁰C₄.

Step by step

  1. Substitute n = 10, r = 4; keep four factors on top.
  2. Compute.

Final answer

¹⁰C₄ = 210.

IB-style question — find one coefficient

Find the coefficient of x³ in the expansion of (1 + x)⁴.

Step by step

  1. Use row 4 of Pascal's triangle — 1, 4, 6, 4, 1 — as the coefficients. The first term is 1, and 1 to any power is still 1, so those numbers sit straight in front of 1, x, x², x³, x⁴.
  2. Pick out the x³ term: it is 4x³, so the coefficient is 4.
  3. The 4 is exactly ⁴C₃ — and you read both numbers off the question: the top (4) is the power on the bracket, (1 + x)⁴, and the bottom (3) is the power of x you want, x³. So for a power too big to write out, just work out that one number.

Final answer

The coefficient of x³ is 4 (which is ⁴C₃). For a big power, get it straight from nCr instead of expanding.

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GDC tip (Paper 2): On the GDC: type n, then MATH → ▶ (PRB) → 3: nCr, then r.

So 4 nCr 3 = 4 here — and for a big one like 10 nCr 4 = 210, the GDC is far faster than drawing the whole triangle.

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Putting it together: The binomial theorem writes (a + b)ⁿ as a sum of terms nCr aⁿ⁻ʳ bʳ — with exactly n + 1 terms.
Coefficients nCr; powers of a fall, powers of b rise, and in every term they sum to n.

IB-style question — read the structure

Write out the structure of (a + b)⁵.

Step by step

  1. Row 5 coefficients (six of them).
  2. Powers of a fall 5 → 0; powers of b rise 0 → 5.

Final answer

Six terms (n + 1 = 5 + 1).

How many terms?: (a + b)ⁿ always has n + 1 terms.

The power of a counts down from n to 0; the power of b counts up from 0 to n; in every term the two powers sum to n.

An exam-style question

Show that .

Step by step

  1. Put the numbers in. With and , write the choose formula before working anything out.
  2. Cancel, then work it out. The on the top and bottom cancel, leaving . Show this working, not just the answer.

Final answer

So , as required.

To get full marks

  • Show the calculation: write and the cancel step .
  • State the result: 120.
  • On a show-that, writing only 120 with no steps can cost you — show the method that reaches the number.

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Write down the number of terms in the expansion of . [1 mark]

Related Math AA Topics

Continue learning with these related topics from the same unit:

1.1.1Writing standard form1.1.2Standard form by hand1.2.1nth term1.2.2Sum of n terms
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Improve your exam techniqueCommand terms, paper structure, and mark-scheme tips for Math AA
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