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NotesMath AA HLTopic 3.2Area of a triangle
Back to Math AA HL Topics
3.2.35 min read

Area of a triangle (Math AA HL)

IB Mathematics: Analysis and Approaches • Unit 3

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Contents

  • Area = ½ab·sinC
  • Finding the area
  • Working backwards
  • Combining with the other rules
Two sides and the angle between them: When you know two sides and the angle between them (the included angle), the area is ½ × (one side) × (other side) × sin(included angle).

Interactive: tap Area to highlight the two sides (a, b) and the included angle (C) that the formula ½ab·sin C uses.

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a and b are the two sides; C is the angle BETWEEN them — in the booklet.
C must be the included angle: The angle in the formula must sit between the two sides you use — not just any angle of the triangle.

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Substitute and evaluate: Identify the two sides and the angle between them, drop them into ½ab·sinC, and evaluate.

IB-style question — straight area

A triangle has sides 6 and 8 with an included angle of 30°. Find its area.

Step by step

  1. Substitute.
  2. Evaluate (sin 30° = ½).

Final answer

Area = 12.

Area = ½ × (the two sides) × sin(the angle BETWEEN them). Sides 6 and 8 meet at 30°: Area = ½(6)(8)sin 30° = 12.

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Pick the right two sides: Use the two sides that enclose the given angle — if a different angle is given, use the sides next to it.

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Given the area, find a side or the angle: Set ½ab·sinC equal to the given area and solve for the unknown — a side (rearrange) or the included angle (then use sin⁻¹, watching for the obtuse possibility).

IB-style question — find the angle

A triangle with sides 10 and 12 has area 30. Find the included angle (acute).

Step by step

  1. Set up.
  2. Solve.

Final answer

C = 30° (the acute solution).

Working backwards from the area: ½(10)(12)sin C = 30 → sin C = 0.5 → C = 30° (sin C = 0.5 also gives 150° — choose from the context).

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Two possible angles: sin C = 0.5 also gives C = 150°. Use the context (or 'acute/obtuse') to choose — both can give the same area.
Find a missing side/angle first, then the area: Many questions need a two-step approach: use the sine or cosine rule to find a missing side or the included angle, then apply ½ab·sinC.

IB-style question — cosine rule then area

A triangle has sides 5 and 7 with included angle 80°. Find its area, then the third side.

Step by step

  1. Area directly (included angle given).
  2. Third side by the cosine rule.

Final answer

Area ≈ 17.2; third side ≈ 7.86.

Sides 5 and 7 meet at 80°. Area = ½(5)(7)sin 80° ≈ 17.2; the third side a (opposite the 80°) comes from the cosine rule, a² = 5² + 7² − 2(5)(7)cos 80° → a ≈ 7.86.

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Read what you're given: If the included angle is missing, find it first (cosine rule from SSS, or sine rule); the area formula needs it.

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A triangle has sides 9 and 10 with an included angle of 40°. Find its area, to 3 s.f. [2 marks]

Related Math AA HL Topics

Continue learning with these related topics from the same unit:

3.1.1Distance & midpoint (3D)
3.1.2Volume & surface area
3.1.3Angles in 3D
3.1.4Solids in 3D coordinates
View all Math AA HL topics

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