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NotesMath AA HLTopic 3.3Elevation & depression
Back to Math AA HL Topics
3.3.15 min read

Elevation & depression (Math AA HL)

IB Mathematics: Analysis and Approaches • Unit 3

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Contents

  • What the angles mean
  • Elevation — find a height or distance
  • Depression and the alternate angle
  • Two observers / two-step problems
Measured from the horizontal: An angle of elevation is measured upward from the horizontal to a point above you; an angle of depression is measured downward from the horizontal to a point below you.

Interactive: switch between an angle of elevation (looking up) and an angle of depression (looking down) — both measured from the horizontal.

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Always sketch the horizontal: Draw the horizontal line at the observer's eye first — the angle is between that line and the line of sight.
Not from the vertical: These angles are from the horizontal, never the vertical — a common slip that flips the right ratio.

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It's a right-angled triangle: Elevation problems form a right-angled triangle: the height is opposite the angle, the ground distance is adjacent. Use tan (or sin/cos as needed).

IB-style question — height of a tower

From a point 50 m from the base of a tower, the angle of elevation to the top is 30°. Find the height of the tower.

Step by step

  1. Opposite (height) and adjacent (50) → tan.
  2. Solve.

Final answer

About 28.9 m.

The elevation triangle: the 30° angle of elevation is at the observer, the tower height h is opposite it, and the 50 m ground distance is adjacent. tan 30° = h ÷ 50 → h ≈ 28.9 m.

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Add eye height if given: If the angle is measured from a person's eye (e.g. 1.6 m up), add that to the triangle's height for the true total.

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Depression down = elevation up: The angle of depression from a high point down to an object equals the angle of elevation from the object back up — they're alternate angles between two parallel horizontals.

Tap 'Depression' (or 'Both'): the angle of depression from the high point and the angle of elevation back up from the object are equal — alternate angles between the two parallel horizontals. That lets you mark the angle low down, inside the right-angled triangle, as in the boat question below.

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IB-style question — depression to a boat

From the top of a 40 m cliff, the angle of depression to a boat is 20°. Find the boat's distance from the base of the cliff.

Step by step

  1. The depression (20°) equals the elevation from the boat, so tan 20° = 40/d.
  2. Solve.

Final answer

About 110 m.

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Use the angle inside the triangle: Mark the equal alternate angle at the bottom so the right-angled triangle has the angle in a usable place.
Non-right triangle → sine/cosine rule: When two observation points (or two towers) and an object form a non-right triangle, the sine or cosine rule does the work — exactly as in the audited two-tower elevation question.

IB-style question — two towers

From a point between two tower tops, the slant distances to the tops are 100 m and 160 m, and the distance between the two tops is 170 m. Find the angle at the point.

Step by step

  1. Three sides → cosine rule for the angle.
  2. Evaluate.

Final answer

About 78.0°.

The two towers and the point form a triangle: the slant distances 100 and 160 meet at the point (the angle θ), and 170 is the side opposite. Three sides → cosine rule for θ: cos θ = (100² + 160² − 170²)/(2·100·160) → θ ≈ 78.0°.

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Elevation gives one angle: An elevation angle from the same point becomes one angle of the bigger triangle — then a right-triangle step finds a height.

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A ramp rises 2 m over a horizontal distance of 9 m. Find the angle of elevation of the ramp, to 3 s.f. [2 marks]

Related Math AA HL Topics

Continue learning with these related topics from the same unit:

3.1.1Distance & midpoint (3D)
3.1.2Volume & surface area
3.1.3Angles in 3D
3.1.4Solids in 3D coordinates
View all Math AA HL topics

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