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NotesMath AA HLTopic 1.14De Moivre's theorem — powers
Back to Math AA HL Topics
1.14.22 min read

De Moivre's theorem — powers (Math AA HL)

IB Mathematics: Analysis and Approaches • Unit 1

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Contents

  • Raising to a power
  • Bigger powers made easy
Power the length, multiply the angle: To raise a complex number to a power, switch to polar form and use De Moivre's theorem:

(r cisθ)ⁿ = rⁿ cis(nθ) — raise the modulus to the power, and multiply the argument by n.
De Moivre's theorem — power the modulus, multiply the angle by n.

Powers of cis(π/6): each power adds π/6 to the angle while staying on the unit circle.

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IB-style question — a high power

Find (1 + i)⁸.

Step by step

  1. Put 1 + i in polar form: r = √2, θ = π/4.
  2. Apply De Moivre: power the modulus, ×8 the angle.
  3. cis(2π) = 1 (a full turn).

Final answer

16.

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Why not just multiply it out?: Expanding (√3 + i)⁶ by hand would mean a huge binomial expansion. De Moivre turns it into one power and one multiplication — far faster and less error-prone.

IB-style question — sixth power

Find (√3 + i)⁶.

Step by step

  1. Polar form: r = √(3 + 1) = 2, θ = arctan(1/√3) = π/6.
  2. De Moivre with n = 6.
  3. cis(π) = −1.

Final answer

−64.

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Find (3 cis(π/9))³ in polar form. [2 marks]

Related Math AA HL Topics

Continue learning with these related topics from the same unit:

1.1.1Writing standard form
1.1.2Standard form by hand
1.10.1Arrangements (order matters)
1.10.2Selections (order doesn't matter)
View all Math AA HL topics

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1.14.1Complex roots come in pairs
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11 practice questions on De Moivre's theorem — powers

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