Back to Topic 3.9 — Reciprocal & inverse trig (HL only)
3.9.2Math AA HL8 flashcards

Inverse trig functions

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Card 1 of 83.9.2
3.9.2
Question

Why does sine need a restricted domain to have an inverse?

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All 8 Flashcards — Inverse trig functions

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Card 1concept

Question

Why does sine need a restricted domain to have an inverse?

Answer

Over all reals sine repeats, so sin x = c has many solutions. Restricting to [−π/2, π/2] makes it one-to-one, so it can be reversed.

Card 2formula

Question

Domain and range of arcsin x?

Answer

Domain [−1, 1], range [−π/2, π/2].

Card 3formula

Question

Domain and range of arccos x?

Answer

Domain [−1, 1], range [0, π].

Card 4formula

Question

Domain and range of arctan x?

Answer

Domain all real numbers, range (−π/2, π/2) (open).

Card 5concept

Question

Exact value of arctan(√3)?

Answer

π/3, since tan(π/3) = √3 and π/3 is in (−π/2, π/2).

Card 6concept

Question

Exact value of arccos(−1/2)?

Answer

2π/3 (cosine is −1/2 there, and 2π/3 is in [0, π]).

Card 7concept

Question

Simplify cos(arcsin x).

Answer

Let θ = arcsin x ⇒ sin θ = x; cos θ = √(1 − x²) (non-negative on [−π/2, π/2]).

Card 8concept

Question

How do you sketch y = arcsin x from y = sin x?

Answer

Take the rising piece of sine on [−π/2, π/2] and reflect it in the line y = x.

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