Back to Topic 1.2 — Arithmetic sequences & series
1.2.2Math AA SL SL11 flashcards

Sum of n terms

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Card 1 of 111.2.2
1.2.2
Question

You are given u₁ = 7 and d = 4 and asked for the sum of the first 20 terms. What do you reach for — and what is the time-trap?

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All 11 Flashcards — Sum of n terms

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Card 1concept

Question

You are given u₁ = 7 and d = 4 and asked for the sum of the first 20 terms. What do you reach for — and what is the time-trap?

Answer

Go straight to Sₙ = (n/2)(2u₁ + (n − 1)d): S₂₀ = 10(14 + 19×4) = 900. Trap: do not waste time finding u₂₀ first — the u₁-and-d form needs only what you are given.

Card 2concept

Question

A question asks 'how many terms until the running total first passes 500?'. How do you set it up?

Answer

It is a TOTAL, so use the sum: set Sₙ > 500 and solve for n, then round UP to the next whole number (on Paper 2, scan the GDC table of Sₙ). Spot 'total/altogether' ⇒ Sₙ, not uₙ.

Card 3concept

Question

How do you choose which sum formula to use?

Answer

Know u₁ and d → use (n/2)(2u₁ + (n − 1)d). Know u₁ and the last term → use (n/2)(u₁ + uₙ).

Card 4formula

Question

If you are told Sₙ as a formula, how do you find the first term?

Answer

u₁ = S₁ — substitute n = 1 into the sum. Example: Sₙ = 2n² + 3n ⇒ u₁ = 5.

Card 5formula

Question

How do you recover any term from a sum formula Sₙ?

Answer

uₙ = Sₙ − Sₙ₋₁ — the running total up to n minus the running total up to n − 1.

Card 6concept

Question

How can you tell a sequence is arithmetic from its sum?

Answer

Its sum is a quadratic in n with no constant term (Sₙ = an² + bn). The common difference is 2a.

Card 7concept

Question

In an arithmetic sequence u₅ = 20 and S₅ = 70. How do you find u₁?

Answer

Use S₅ = (5/2)(u₁ + u₅): 70 = (5/2)(u₁ + 20) ⇒ u₁ + 20 = 28 ⇒ u₁ = 8.

Card 8concept

Question

Why is there a factor of n/2 in the sum formula?

Answer

Pairing the first and last terms gives a constant total u₁ + uₙ, and there are n/2 such pairs, so Sₙ = (n/2)(u₁ + uₙ).

Card 9concept

Question

How do you find d when given two sums, e.g. S₅ and S₆?

Answer

u₆ = S₆ − S₅ gives a term; combined with the sum formula you can solve for u₁ and d.

Card 10concept

Question

Find S₈ for u₁ = 10, u₈ = 45.

Answer

S₈ = (8/2)(10 + 45) = 4 × 55 = 220.

Card 11definition

Question

What is the difference between Sₙ and uₙ?

Answer

uₙ is a single term (the nth one); Sₙ is the total of the first n terms: Sₙ = u₁ + u₂ + … + uₙ.

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IB Math AA SL Sum of n terms Flashcards | 1.2.2 | Aimnova | Aimnova