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v0.1.1437
NotesChemistry HLTopic 3.2Organic compounds and homologous series
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3.2.13 min read

Organic compounds and homologous series

IB Chemistry • Unit 3

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Contents

  • What is a homologous series?
  • General formulas and the CH₂ step
  • Saturated vs unsaturated
  • Exam-style question
The big idea: Organic chemistry is the chemistry of carbon compounds. There are millions of them, so chemists organise them into families called homologous series.

A homologous series is a family of organic compounds that share the same general formula and the same functional group, where each member differs from the next by a CH_{2} unit.

- Functional group — the reactive atom or group of atoms that gives a series its characteristic chemistry (e.g. the C=C of alkenes, the –OH of alcohols). - General formula — a single formula, in terms of the number of carbons n, that fits every member (e.g. alkanes are CnH2n+2).

Three carbons, all single C–C bonds (saturated). Each added carbon adds one CH2 unit.

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The four features of a series: Every homologous series has these four features:

- Members fit one general formula. - Successive members differ by CH_{2}. - They show a gradual change in physical properties (e.g. boiling point rises down the series). - They have similar chemical properties (because they share the same functional group).

Because every member differs by CH_{2}, each series can be summed up by a single general formula written in terms of the number of carbon atoms, n. Substitute n = 1, 2, 3, … to generate the members.

SeriesGeneral formulaFunctional groupFirst member
AlkanesCnH2n+2none (only C–C, C–H)methane, CH4
AlkenesCnH2nC=C double bondethene, C2H4
AlcoholsCnH2n+1OH–OH (hydroxyl)methanol, CH3OH
Building the alkanes: The alkane general formula is C_{n}H_{2n+2}:

- n = 1 → CH4 (methane) - n = 2 → C2H6 (ethane) - n = 3 → C3H8 (propane) - n = 4 → C4H10 (butane)

Notice each step adds one C and two H — exactly one CH2 unit.

The next alkane: one more carbon than propane, so one extra CH2.

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Why properties change gradually: As the chain gets longer, the molecules get bigger and heavier, so the intermolecular forces between them get stronger. That is why boiling point rises steadily down a homologous series — a smooth, predictable trend, not random jumps.

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A key way to classify organic molecules is by whether they contain a carbon–carbon double bond. This is the difference between saturated and unsaturated compounds.

Saturated (alkanes)

  • Only single C–C bonds.
  • Contain the maximum number of hydrogen atoms.
  • General formula C_{n}H_{2n+2}.
  • Example: propane, C3H8.

Unsaturated (alkenes)

  • Contain at least one C=C double bond.
  • Have fewer hydrogens than the matching alkane.
  • General formula C_{n}H_{2n}.
  • Example: but-1-ene, C4H8.

An alkene: the C=C double bond between the first two carbons makes it unsaturated.

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Same carbons, fewer hydrogens: Compare butane (C4H10, saturated) with but-1-ene (C4H8, unsaturated): both have 4 carbons, but the double bond means the alkene holds 2 fewer hydrogens. The C=C is the functional group that makes alkenes reactive (e.g. they decolourise bromine water).
How this is tested: S3.2 reliably opens with a quick recall mark. The most common ask is to state the general formula of a named homologous series (alkanes, alkenes or alcohols) on Paper 2, or a Paper 1A MCQ that tests whether you can spot the CH_{2} difference or classify a molecule as saturated/unsaturated.

The general formula must be written in terms of n — a specific formula like C2H4 will not earn the mark.
Memorise the three formulas: Learn these cold: alkanes C_{n}H_{2n+2}, alkenes C_{n}H_{2n}, alcohols C_{n}H_{2n+1}OH. The alkene is the alkane minus 2 H (the double bond), which is the detail students forget.

IB-style question — general formula of alkenes

But-1-ene, C4H8, is a member of the alkene homologous series. State the general formula of the alkenes. [1]

How to score the mark

  1. Check the pattern: for an alkene with n = 4 carbons there are 8 hydrogens, so the number of H atoms is twice the number of C atoms (2 × 4 = 8).
  2. Write it in terms of n: the general formula is C_{n}H_{2n} — this is the form the markers require, not a specific formula such as C4H8.

Final answer

CnH2n.

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the general formula of the homologous series of alkanes, and why successive members differ by CH2. [2] [2 marks]

Related Chemistry HL Topics

Continue learning with these related topics from the same unit:

3.1.1The periodic table: periods, groups and blocks
3.1.2Periodic trends in atomic properties
3.1.3Chemical trends of groups and period 3
3.2.2Representing organic molecules
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