Calorimetry and calculating enthalpy change
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Question
What is calorimetry?
Answer
Measuring the **temperature change** of a known mass of water (or solution) to find the heat transferred by a reaction.
Question
What is specific heat capacity, c?
Answer
The energy needed to raise **1 g** of a substance by **1 K** (1 °C). For water, **c = 4.18 J g⁻¹ K⁻¹**.
Question
Equation for heat transferred?
Answer
$Q = mc\Delta T$ — heat (J) = mass (g) × specific heat capacity × temperature change.
Question
How do you find ΔT?
Answer
ΔT = **T_{final} − T_{initial}**. A change of 1 °C equals a change of 1 K, so the number is the same.
Question
How do you get ΔH per mole from Q?
Answer
$\Delta H = -\dfrac{Q}{n}$ — divide Q (in kJ) by the amount that reacted, and add the sign.
Question
Temperature rises — exo or endo, and the sign?
Answer
**Exothermic** — heat released to the water — so **ΔH is negative**.
Question
Temperature falls — exo or endo, and the sign?
Answer
**Endothermic** — heat absorbed from the water — so **ΔH is positive**.
Question
Which mass goes into Q = mcΔT?
Answer
The mass of **water** (the substance heated), **not** the mass of fuel or reactant.
Question
Why convert J to kJ in calorimetry?
Answer
Q from $mc\Delta T$ is in **joules**; enthalpy changes are quoted in **kJ mol⁻¹**, so divide by 1000.
Question
Main source of error in combustion calorimetry?
Answer
**Heat loss** to the surroundings and apparatus — so the measured ΔH is **less exothermic** than the true value.
Question
Two assumptions in the Q = mcΔT calculation?
Answer
All the heat goes to the **water**, and the **specific heat capacity** (and density) of the solution equals that of water.
Question
Order of steps in a calorimetry calculation?
Answer
ΔT → **Q = mcΔT** → ÷1000 for kJ → **÷ n** for per mole → add the **sign**.
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Topic 4.1 hub
Measuring enthalpy change
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