Back to Topic 2.2 — The covalent model
2.2.3Chemistry SL11 flashcards

Bond polarity and electronegativity

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Card 1 of 112.2.3
2.2.3
Question

What is electronegativity?

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All 11 Flashcards — Bond polarity and electronegativity

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Card 1definition

Question

What is electronegativity?

Answer

A measure of how strongly an atom **attracts the shared (bonding) electrons** in a covalent bond.

Card 2concept

Question

What makes a bond polar?

Answer

A **difference in electronegativity** between the two atoms — the electrons are pulled towards the more electronegative atom.

Card 3concept

Question

Which atom becomes δ−?

Answer

The **more electronegative** atom (it gets a bigger share of the electrons); the less electronegative atom is **δ+**.

Card 4comparison

Question

Pure covalent vs polar covalent vs ionic?

Answer

Δχ = 0 → **pure covalent**; small Δχ → **polar covalent** (δ+/δ−); large Δχ → **ionic**.

Card 5definition

Question

What is a bond dipole?

Answer

The small separation of charge (δ+ → δ−) along a polar bond; drawn as an **arrow** pointing to the δ− atom.

Card 6concept

Question

When is a molecule with polar bonds non-polar?

Answer

When the molecule is **symmetrical**, so the bond dipoles **cancel** (e.g. CO_{2}, CCl_{4}, BF_{3}).

Card 7example

Question

Why is CO_{2} non-polar?

Answer

It is **linear** — the two equal C=O dipoles point in opposite directions and **cancel**.

Card 8example

Question

Why is H_{2}O polar?

Answer

It is **bent** (lone pairs on O), so the two O–H dipoles **do not cancel** and give a net dipole.

Card 9example

Question

Does NH_{3} have a net dipole?

Answer

Yes — it is **trigonal pyramidal** (a lone pair on N), so the N–H dipoles do not cancel; NH_{3} is polar.

Card 10concept

Question

What two things must a 'why is X polar?' answer mention?

Answer

(1) the bonds are **polar** (electronegativity difference) and (2) the **shape** means the dipoles **do not cancel**.

Card 11example

Question

Is Cl_{2} polar?

Answer

No — both atoms are identical, so Δχ = 0; the bond is **non-polar** and there is no dipole.

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