Back to Topic 1.5 — Ideal gases
1.5.1Chemistry SL12 flashcards

The gas laws

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Card 1 of 121.5.1
1.5.1
Question

State Boyle's law.

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All 12 Flashcards — The gas laws

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Card 1definition

Question

State Boyle's law.

Answer

At **constant temperature** (and amount), the pressure of a gas is **inversely proportional** to its volume: $P_{1}V_{1} = P_{2}V_{2}$.

Card 2concept

Question

How is pressure related to temperature at constant volume?

Answer

Pressure is **directly proportional** to the **kelvin** temperature: $\dfrac{P_{1}}{T_{1}} = \dfrac{P_{2}}{T_{2}}$.

Card 3formula

Question

Write the combined gas law.

Answer

$\dfrac{P_{1}V_{1}}{T_{1}} = \dfrac{P_{2}V_{2}}{T_{2}}$ — with T in **kelvin**. It is given in the data booklet.

Card 4formula

Question

How do you convert °C to kelvin?

Answer

**T/K = θ/°C + 273** — always do this before a gas-law calculation.

Card 5concept

Question

What are the assumptions of an ideal gas?

Answer

The particles have **no volume** of their own and there are **no forces** between them.

Card 6concept

Question

When does a real gas behave most ideally?

Answer

At **high temperature** and **low pressure** — particles are far apart and fast-moving.

Card 7concept

Question

When does a gas deviate most from ideal?

Answer

At **low temperature** and **high pressure** — particle volume and intermolecular forces become significant.

Card 8concept

Question

If the volume of a fixed gas sample is doubled at constant T, what happens to P?

Answer

The pressure **halves** (Boyle's law: P ∝ 1/V).

Card 9concept

Question

Why must temperature be in kelvin for the gas laws?

Answer

Only the **kelvin** scale starts at true zero (0 K), so only it gives the correct proportionality; °C would give wrong ratios.

Card 10concept

Question

On a P–T graph (constant V), why does the line pass through the origin?

Answer

Because P ∝ kelvin T — at 0 K the particles would stop and the pressure would be **zero**.

Card 11definition

Question

What is held constant in Boyle's law?

Answer

The **temperature** and the **amount** of gas; only P and V change.

Card 12formula

Question

How do you find a new pressure when V and T both change?

Answer

Use the combined gas law: $P_{2} = P_{1}\times\dfrac{V_{1}}{V_{2}}\times\dfrac{T_{2}}{T_{1}}$ (T in kelvin).

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