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NotesMath AA HLTopic 2.9Logarithmic functions
Back to Math AA HL Topics
2.9.23 min read

Logarithmic functions (Math AA HL)

IB Mathematics: Analysis and Approaches • Unit 2

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Contents

  • The shape of y = logₐx
  • Log is the inverse of exponential
  • Key features & sketch
  • Transformed logarithms
Through (1, 0), hugging the y-axis: The logarithm y = logₐx (a > 1) passes through (1, 0) (because logₐ1 = 0), rises slowly, and has the vertical asymptote x = 0 — it's only defined for x > 0.

IB-style question — key points of log

State the x-intercept and vertical asymptote of y = log x.

Step by step

  1. x-intercept: y = 0.
  2. As x → 0⁺, log x → −∞.

Final answer

x-intercept (1, 0); vertical asymptote x = 0.

You can't log zero or a negative: logₐx is only defined for x > 0. There's no y-intercept (x = 0 isn't allowed).

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Reflections in y = x: y = logₐx is the inverse of y = aˣ — each is the other reflected in the line y = x. So their key features swap: aˣ goes through (0, 1) with asymptote y = 0; logₐx goes through (1, 0) with asymptote x = 0.

y = aˣ

  • through (0, 1)
  • asymptote y = 0
  • domain all x, range y > 0

y = logₐx (its inverse)

  • through (1, 0)
  • asymptote x = 0
  • domain x > 0, range all y
Domain ↔ range swap: Because they're inverses, the domain of the log is the range of the exponential (x > 0), and vice versa.

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Asymptote x = 0, x-intercept (1, 0): To sketch y = logₐx (a > 1): draw the vertical asymptote x = 0, mark the x-intercept (1, 0), and curve upward to the right (slowly increasing, defined only for x > 0).

IB-style question — domain & range

State the domain and range of y = log x.

Step by step

  1. Only positive inputs allowed.
  2. Outputs cover every real value.

Final answer

Domain x > 0; range y ∈ ℝ.

It increases forever, slowly: log x keeps rising as x grows, but ever more slowly — there's no horizontal asymptote.
The inside shifts the asymptote: y = logₐ(x − h) + k shifts the graph h right and k up. The vertical asymptote moves to x = h, and the domain becomes x > h (the inside must stay positive).

IB-style question — shifted log

State the vertical asymptote and domain of y = log(x − 2).

Step by step

  1. Inside must be positive.
  2. Asymptote where the inside is 0.

Final answer

Vertical asymptote x = 2; domain x > 2.

Domain follows the asymptote: For logₐ(x − h), the domain is x > h — everything to the right of the vertical asymptote.

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the domain and range of y = log x. [2 marks]

Related Math AA HL Topics

Continue learning with these related topics from the same unit:

2.1.1Equations of lines
2.1.2Parallel lines
2.1.3Perpendicular lines
2.1.4Perpendicular bisector
View all Math AA HL topics

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