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Topic 5.2Physics HL28 flashcards

Quantum physics (HL)

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Card 1 of 285.2.1
5.2.1
Question

What is a photon?

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All Flashcards in Topic 5.2

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5.2.115 cards

Card 1definition
Question

What is a photon?

Answer

A **quantum (packet) of light energy**, E = hf.

Card 2formula
Question

Photon energy formula?

Answer

$E = hf$ (or $E = hc/\lambda$); h = 6.63×10⁻³⁴ J s.

Card 3definition
Question

What is the photoelectric effect?

Answer

Light ejecting **electrons** from a metal surface.

Card 4formula
Question

The photoelectric equation?

Answer

$E_{\max} = hf - \Phi$ (max electron KE = photon energy − work function).

Card 5definition
Question

What is the work function Φ?

Answer

The **minimum energy** needed to free an electron from the metal.

Card 6concept
Question

What is the threshold frequency?

Answer

The lowest frequency that ejects electrons: $f_0 = \Phi/h$ (where E_max = 0).

Card 7concept
Question

Increase the light's intensity (same frequency) — effect?

Answer

**More** electrons ejected per second; their max KE is **unchanged**.

Card 8concept
Question

Increase the light's frequency — effect on max KE?

Answer

Max KE **increases** (E_max = hf − Φ).

Card 9concept
Question

Why does the photoelectric effect need photons?

Answer

One electron absorbs **one photon**; a sharp threshold can't be explained by a smooth wave.

Card 10comparison
Question

Which effects show light's WAVE nature?

Answer

**Diffraction** and **interference**.

Card 11comparison
Question

Which effect shows light's PARTICLE nature?

Answer

The **photoelectric effect**.

Card 12concept
Question

What is wave–particle duality?

Answer

Light (and matter) behaves as **both** a wave and a particle depending on the experiment.

Card 13concept
Question

Why does a Compton-scattered photon have a longer wavelength?

Answer

It gives some of its **energy and momentum** to the recoiling electron; less energy means a longer wavelength.

Card 14concept
Question

Which photoelectric observations can the wave model of light not explain?

Answer

A **threshold frequency**, E_max set by **frequency** not brightness, and **instant** emission even in dim light.

Card 15concept
Question

What are the gradient and intercepts of a graph of E_max against frequency?

Answer

Gradient **h**; it cuts the f axis at the threshold **f₀** and, extended, the E_max axis at **−Φ**.

5.2.213 cards

Card 16definition
Question

What is a matter wave?

Answer

The **wave** behaviour of a moving particle, with wavelength λ = h/p.

Card 17formula
Question

De Broglie wavelength formula?

Answer

$\lambda = h/p$ (p = mv for a slow particle).

Card 18concept
Question

How does λ depend on momentum?

Answer

**Inversely** — bigger momentum gives a **shorter** wavelength.

Card 19concept
Question

What is the evidence for matter waves?

Answer

**Electron diffraction** — electrons make diffraction patterns off crystals.

Card 20concept
Question

Why does a cricket ball not diffract?

Answer

Its momentum is huge, so λ = h/p is far too small (~10⁻³⁴ m) to notice.

Card 21process
Question

Steps to find a de Broglie wavelength?

Answer

Find **p = mv** first, then **λ = h/p**.

Card 22concept
Question

How does the angle of the first diffraction minimum depend on the electrons' wavelength?

Answer

**sin θ ≈ λ/b**: a shorter de Broglie wavelength gives a smaller angle.

Card 23concept
Question

What happens to electron diffraction rings when the accelerating voltage is raised?

Answer

They **shrink**: faster electrons have a shorter wavelength, λ = h/√(2meV).

Card 24concept
Question

Why do electrons diffract off crystals but not big slits?

Answer

Their λ (~10⁻¹⁰ m) matches the **atomic spacing**.

Card 25concept
Question

Double a particle's speed — effect on λ?

Answer

λ is **halved** (p doubles, λ = h/p).

Card 26definition
Question

Units of de Broglie wavelength?

Answer

**metres (m)**.

Card 27concept
Question

Wave–particle duality for matter means…

Answer

Particles like electrons show **both** particle and wave behaviour.

Card 28formula
Question

What is the de Broglie wavelength of an electron accelerated from rest through a pd V?

Answer

**λ = h/√(2meV)**, from λ = h/p and eV = p²/2m.

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