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NotesMath AA HLTopic 4.8
Unit 4 · Statistics & Probability · Topic 4.8

IB Math AA HL — Binomial distribution

Topic 4.8 of IB Mathematics: Analysis and Approaches covers Binomial distribution, which is part of Unit 4: Statistics & Probability. Students explore key concepts including Binomial probabilities, Binomial mean and variance. A strong understanding of binomial distribution is essential for IB Math AA HL exams and builds the foundation for connected topics across the syllabus.

Higher Level students should use this topic hub as a map: start with the shared sub-topics, then follow the HL-only extensions and exam-skill links where this topic asks for deeper analysis.

Exam technique guidePractice questions

Key concepts in Binomial distribution

Key Idea: X counts successes. Identify n and p, then use the GDC for the probability asked.

When is it binomial? Fixed attempts · independent · success/failure · constant p. Example: 20 fair die rolls; count sixes → X ~ B(20,1/6).

Mean, variance and SD Mean: np. Variance: np(1 − p). SD: √variance. Example: B(20,0.3) → 6, 4.2, 2.05.

Exactly / at most / fewer than Exactly 7: binompdf(n,p,7). At most 7: binomcdf(n,p,7). Fewer than 7: binomcdf(n,p,6).

At least / more than / between At least 7: 1 − binomcdf(n,p,6). More than 7: 1 − binomcdf(n,p,7). Between 3 and 8: CDF(8) − CDF(2).

Working backwards Expected limit: write np ≤ limit, then solve. Example: 0.9n ≤ 54 → n ≤ 60. Check 61 fails. Probability limit: test integers and check the neighbour.

More than one stage Find p first: two independent checks → 0.8 × 0.9 = 0.72. Expected repeated events: find whole-event probability q; then Nq. Example: 25 batches × q ≈ 7.59 qualifying batches.

IB-style question [6 marks]

An online shop knows that, independently, 20% of all orders are returned. On a particular day it receives 15 orders. Let X be the number of these orders that are returned. (a) Write down the expected number of returned orders. (b) Find the probability that exactly 2 orders are returned. (c) Find the probability that at least 4 orders are returned.

Step by step:

  1. Each order is independent with a constant return probability, so X is binomial with n = 15 and p = 0.2.

    X∼B(15, 0.2)X \sim B(15,\ 0.2)X∼B(15, 0.2)
  2. (a) The expected number is the binomial mean np.

    E(X)=np=15×0.2=3E(X) = np = 15 \times 0.2 = 3E(X)=np=15×0.2=3
  3. (b) 'Exactly 2' uses the single-value probability binompdf.

    P(X=2)=binompdf⁡(15,0.2,2)≈0.231P(X=2)=\operatorname{binompdf}(15,0.2,2)\approx0.231P(X=2)=binompdf(15,0.2,2)≈0.231
  4. (c) 'At least 4' is the complement of 'at most 3', so subtract the cumulative probability up to 3.

    P(X≥4)=1−P(X≤3)P(X \ge 4) = 1 - P(X \le 3)P(X≥4)=1−P(X≤3)
  5. Use binomcdf(15, 0.2, 3), then subtract from 1.

    P(X≥4)=1−0.6482=0.352 (3 s.f.)P(X \ge 4) = 1 - 0.6482 = 0.352\ (3\text{ s.f.})P(X≥4)=1−0.6482=0.352 (3 s.f.)
Final answer:

(a) 3 orders. (b) 0.231. (c) 0.352.

Exam checklist State X, n and p. Check whether the boundary is included. Show the event or calculator setup. Keep intermediate values unrounded.

IB-style question — exactly, at most, at least

A spinner lands on red with probability 0.35. It is spun 14 times. Let X be the number of reds. Find (a) P(X = 5), (b) P(X ≤ 4), (c) P(X ≥ 6).

Step by step:

  1. State the model.

    X∼B(14, 0.35)X \sim B(14,\,0.35)X∼B(14,0.35)
  2. (a) Exactly 5 → binompdf(14, 0.35, 5).

    P(X=5)≈0.218P(X = 5) \approx 0.218P(X=5)≈0.218
  3. (b) At most 4 → binomcdf(14, 0.35, 4).

    P(X≤4)≈0.423P(X \le 4) \approx 0.423P(X≤4)≈0.423
  4. (c) At least 6 is the complement of ≤ 5.

    P(X≥6)=1−binomcdf(14,0.35,5)≈0.359P(X \ge 6) = 1 - \text{binomcdf}(14, 0.35, 5) \approx 0.359P(X≥6)=1−binomcdf(14,0.35,5)≈0.359
Final answer:

(a) 0.218 (b) 0.423 (c) 0.359 (3 s.f.).

IB-style question — find the mean, variance and standard deviation

A quiz has 40 independent questions, each guessed correctly with probability 0.25. Let X be the number correct. Find the mean, variance and standard deviation of X.

Step by step:

  1. Mean = np.

    E(X)=40×0.25=10E(X) = 40 \times 0.25 = 10E(X)=40×0.25=10
  2. Variance = np(1 − p).

    Var(X)=40×0.25×0.75=7.5\text{Var}(X) = 40 \times 0.25 \times 0.75 = 7.5Var(X)=40×0.25×0.75=7.5
  3. Standard deviation = √variance.

    σ=7.5≈2.74\sigma = \sqrt{7.5} \approx 2.74σ=7.5​≈2.74
Final answer:

Mean = 10, variance = 7.5, standard deviation ≈ 2.74.

AA exam practice: key methods

Question typeRemember
mean linked to standard deviationDo not confuse variance with standard deviation. Check roots in the original equation after squaring.
a success on the final trialThis is not just “three successes in five trials”: that would include orders whose third success occurs earlier. The GDC calculates the binomial part.

What you'll learn in Topic 4.8

  • 4.8.1 Binomial probabilities
  • 4.8.2 Binomial mean and variance
Suggested study order: Read the notes for each sub-topic below → test yourself with flashcards → attempt practice questions → review exam technique.

Study resources — 4.8 Binomial distribution

4.8.1

Binomial probabilities

Notes
4.8.2

Binomial mean and variance

Notes

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Topic 4.8 Binomial distribution forms a core part of Unit 4: Statistics & Probability in IB Math AA HL. Mastering these concepts will strengthen your understanding of connected topics across the syllabus and prepare you for exam questions that require analysis, evaluation, and real-world application.

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