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NotesMath AA HLTopic 3.4Arc length & sector area
Back to Math AA HL Topics
3.4.23 min read

Arc length & sector area (Math AA HL)

IB Mathematics: Analysis and Approaches • Unit 3

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Contents

  • Arc length s = rθ
  • Sector area A = ½r²θ
  • Working backwards
  • Perimeter & segments
Radius times the angle (in radians): The arc length of a sector is s = rθ, where θ is the central angle in radians. (It's a fraction θ/2π of the whole circumference 2πr.)

Interactive: change the sector angle and watch the arc length (s = rθ) and sector area (½r²θ) update.

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Arc length — in the formula booklet.

IB-style question — arc length

A sector has radius 8 and central angle π/3. Find the arc length.

Step by step

  1. Use s = rθ.
  2. Evaluate.

Final answer

Arc length = 8π/3 ≈ 8.38.

θ MUST be in radians: s = rθ only works with θ in radians — convert a degree angle first.

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Half r-squared times the angle: The area of a sector is A = ½r²θ, with θ in radians (a fraction θ/2π of the whole circle area πr²).
Sector area — in the formula booklet.

IB-style question — sector area

A sector has radius 6 and central angle 1.5 radians. Find its area.

Step by step

  1. Use A = ½r²θ.
  2. Evaluate.

Final answer

Area = 27.

The sector from the question: radius 6, angle 1.5 rad. Area = ½r²θ = ½ × 36 × 1.5 = 27 (θ must be in radians).

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Square the radius first: Work out r² before multiplying by the angle and the ½ — keeps the arithmetic clean.

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Rearrange for r or θ: Given an arc length or sector area, substitute and solve for the unknown radius or angle. From s = rθ: θ = s/r. From A = ½r²θ: solve for whichever is missing.

IB-style question — find the angle

A sector of radius 5 has arc length 15. Find the central angle θ.

Step by step

  1. Use s = rθ.
  2. Solve.

Final answer

θ = 3 radians.

Working backwards: radius 5, arc length 15, so θ = s/r = 15/5 = 3 rad — a wide sector (3 rad ≈ 172°, nearly a half-turn).

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Cancel π if it appears: If both sides carry π (e.g. area = 6π), divide it out before solving — the numbers simplify.
Perimeter = arc + two radii; segment = sector − triangle: The perimeter of a sector is the arc plus the two straight radii (s + 2r). The area of a segment (between a chord and the arc) is the sector area minus the triangle area: ½r²θ − ½r²sinθ.

IB-style question — perimeter then segment

A sector has radius 10 and angle π/2. Find (a) its perimeter and (b) the area of the segment cut off by the chord.

Step by step

  1. (a) Perimeter = arc + 2r.
  2. (b) Segment = sector − triangle.

Final answer

(a) 5π + 20 ≈ 35.7; (b) ≈ 28.5.

Radius 10, angle π/2 (90°). Perimeter = arc + 2r = 5π + 20 ≈ 35.7; the shaded segment (sector − triangle) ≈ 78.5 − 50 = 28.5.

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Triangle uses ½r²sinθ: The triangle between the two radii has area ½r²sinθ (two sides r with included angle θ) — subtract it from the sector for the segment.

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A sector has radius 9 cm and central angle 0.8 radians. Find its arc length. [2 marks]

Related Math AA HL Topics

Continue learning with these related topics from the same unit:

3.1.1Distance & midpoint (3D)
3.1.2Volume & surface area
3.1.3Angles in 3D
3.1.4Solids in 3D coordinates
View all Math AA HL topics

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3.4.1Radian measure
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Unit circle & exact values3.5.1

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