Back to Topic 6.4 — Electron-pair sharing reactions
6.4.3Chemistry12 flashcards

Electrophilic addition and substitution (HL)

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Card 1 of 126.4.3
6.4.3
Question

Why is an alkene's C=C reactive in electrophilic addition?

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All 12 Flashcards — Electrophilic addition and substitution (HL)

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Card 1concept

Question

Why is an alkene's C=C reactive in electrophilic addition?

Answer

It is **electron-rich** — the exposed **π electrons** make it an electron-pair **donor** that attacks an electrophile.

Card 2definition

Question

What is an electrophile?

Answer

An **electron-pair acceptor** — an electron-poor (often positive) species attracted to an electron-rich centre such as a C=C (e.g. δ+ H of HBr, NO_{2}⁺).

Card 3definition

Question

What is a carbocation?

Answer

A carbon atom bearing a **positive charge** (only 3 bonds / 6 electrons) — the reactive **intermediate** in electrophilic addition.

Card 4process

Question

Describe step 1 of HBr adding to an alkene.

Answer

The **C=C π electrons → the δ+ H** of HBr (arrow 1); the **H–Br bond → Br** (arrow 2), which leaves as **Br⁻**. A **carbocation** forms.

Card 5process

Question

Describe step 2 of HBr adding to an alkene.

Answer

The **bromide ion (Br⁻) attacks the positive carbon** of the carbocation, forming the final C–Br bond — the reagent has now **added across** the C=C.

Card 6concept

Question

What is Markovnikov's rule (HL explanation)?

Answer

The major product forms via the **more stable carbocation**; equivalently, the **H of HX adds to the C with more H's**.

Card 7comparison

Question

Order of carbocation stability?

Answer

**tertiary (3°) > secondary (2°) > primary (1°)** — more alkyl groups donate electron density and spread the positive charge.

Card 8example

Question

Major product of propene + HBr, and why?

Answer

**2-bromopropane, CH_{3}CHBrCH_{3}** — via the more stable **secondary** carbocation (Markovnikov).

Card 9example

Question

Major product of 2-methylpropene + HBr?

Answer

**2-bromo-2-methylpropane, (CH_{3})_{3}CBr** — via the most stable **tertiary** carbocation.

Card 10concept

Question

Why does benzene substitute rather than add?

Answer

Its **delocalised** ring is very **stable**; addition would destroy the delocalisation, while **substitution restores** the aromatic ring.

Card 11example

Question

Electrophile, catalyst and product in benzene nitration?

Answer

Electrophile = **nitronium ion, NO_{2}⁺**; catalyst = conc. **H_{2}SO_{4}**; product = **nitrobenzene, C_{6}H_{5}NO_{2}** (plus H⁺ lost).

Card 12comparison

Question

Addition vs substitution — the key difference?

Answer

**Addition**: reagent adds across C=C, nothing leaves (alkenes). **Substitution**: one group replaces a ring H, ring restored (benzene).

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