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c059741
NotesPhysicsTopic 4.3Magnetic force on charges and the velocity selector
Back to Physics Topics
4.3.32 min read

Magnetic force on charges and the velocity selector

IB Physics • Unit 4

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Contents

  • The magnetic force on a moving charge
  • F = qvB and the velocity selector
  • Exam-style question
The big idea: The northern lights glow because charged particles streaming from the Sun get bent into spirals by Earth's magnetic field — any moving charge in a magnetic field feels a sideways force, F = qvB (when it moves at right angles to the field).

This force is always perpendicular to the velocity — it pushes the charge sideways, never forwards or backwards.

A constant sideways push bends the path into a circle.

Magnetic force on a moving charge

  • Size: F = qvB (when v is perpendicular to B)
  • Direction: perpendicular to the velocity v — always sideways
  • A sideways push can't speed it up or slow it down, so it bends the path into a circle of radius r = mv/(qB)

Electric force on a charge (for contrast)

  • Size: F = qE (in a field E)
  • Direction: along the field — parallel to E
  • A push along the motion changes the speed (it can speed up or slow the charge)
Spot it: Stationary charge → no magnetic force (you need v).

The force is sideways, so it can't change the speed — only the direction, curving the charge into a circle.

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The data booklet gives the magnetic force on a moving charge. For a charge moving at right angles to the field (the case the exam tests):

Magnetic force on a moving charge (given in the data booklet as F = qvB sinθ; here the charge moves at right angles to B, so sinθ = 1). F in newtons, q in coulombs, v in m per second, B in tesla.
magnetic force on the charge (N)
size of the moving charge (C)
speed of the charge (m s⁻¹)
magnetic field strength (T, tesla)
What a velocity selector is: A velocity selector sends charges through crossed fields — an electric field E and a magnetic field B at right angles to each other.

The electric force qE pushes one way; the magnetic force qvB pushes the opposite way. Only charges of one exact speed feel zero net force and pass straight through.

A velocity selector has two charged parallel plates making a UNIFORM electric field E (evenly spaced arrows, from the + plate to the − plate). A magnetic field B is also applied across the same gap, at right angles to both E and the charge's motion.

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Inside the selector the electric force qE and the magnetic force qvB act in OPPOSITE directions on the moving charge. When qE = qvB they cancel, the net force is zero, and the charge travels in a straight line — undeflected.

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For the charge to go straight (undeflected) the two forces must be equal. Set them equal and the charge q cancels:

Derived rule
The velocity-selector condition. The selected speed v = E ÷ B does NOT depend on the charge or the mass — every undeflected particle has this same speed.
selected speed — the speed that passes straight through (m s⁻¹)
electric field strength between the plates (N C⁻¹ or V m⁻¹)
magnetic field strength (T)

From qE = qvB the q cancels, leaving E = vB. Cover the one you want: v and B side by side → multiply (E = vB); E above B → divide (v = E ÷ B).

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IB-style questionCalculate[2 marks]

A velocity selector has an electric field of E = 3.0 × 10⁴ N C⁻¹ and a magnetic field of B = 0.20 T, crossed at right angles. Find the speed of a charge that passes straight through undeflected.

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How this is tested — the velocity selector is a classic Paper 2 'crossed fields' question:

Paper 2 — the balance

  • A particle passes undeflected through crossed fields.
  • Find B (or E, or the speed v) from the balance qE = qvB.

Paper 2 — a different particle

  • A different charge then enters the same fields.
  • Draw or describe its path — it curves, because the magnetic force qvB changes.
The classic trap: Don't think the selected speed depends on the charge or mass — it doesn't. From qE = qvB the charge cancels, so v = E ÷ B only.
A different particle deflects: Set B by balancing one particle. A second particle of a different charge or mass moving at a different speed no longer satisfies qE = qvB, so one force wins and it curves.

Slower than v = E/B

  • Magnetic force qvB is smaller (v is smaller)
  • Electric force qE now wins
  • The charge is deflected toward the − plate (the way qE points)

Faster than v = E/B

  • Magnetic force qvB is larger (v is larger)
  • Magnetic force now wins
  • The charge is deflected the other way (the way qvB points)
IB-style questionDetermine[4 marks]

An electron enters a velocity selector at 4.0 × 10⁶ m s⁻¹, where the electric field between the plates is E = 8.0 × 10⁵ N C⁻¹. (a) Find the magnetic field strength B that lets the electron pass through undeflected. (b) A second electron enters the same crossed fields moving faster than 4.0 × 10⁶ m s⁻¹. State whether it passes straight through, and which force wins.

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Try an IB Exam Question — Free AI Feedback

Test yourself on Magnetic force on charges and the velocity selector. Write your answer and get instant AI feedback — just like a real IB examiner.

An ion carrying charge 1.6 × 10⁻¹⁹ C moves at 5.0 × 10⁶ m s⁻¹ at right angles to a magnetic field of strength 0.30 T.

the magnitude of the magnetic force on the ion.
[2 marks]

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