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v0.1.512
NotesMath AI SLTopic 4.9Normal Distribution Properties
Back to Math AI SL Topics
4.9.11 min read

Normal Distribution Properties

IB Mathematics: Applications and Interpretation • Unit 4

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Contents

  • The normal distribution and bell curve
  • The 68-95-99.7 rule
  • Standardizing with z-scores
  • Using z-tables and symmetry
The big idea: Many measurements follow a bell-shaped pattern: symmetric, with values clustered near center and fewer at extremes. This is the normal distribution.

Examples: heights, test scores, measurement errors. Not all data is normal (income is skewed), but natural phenomena often are.

Notation: X ~ N(μ, σ²) where μ is mean and σ² is variance. Sometimes the question gives σ (SD) instead — always check.

Why this matters

Key characteristics

  • Most data clusters near mean.
  • Fewer values far from mean.
  • Curve is symmetric left-right.
  • Mean = median = mode.

The 68-95-99.7 rule

One rule for all normal distributions: No matter what μ and σ are, the percentage of data within fixed distances from the mean is always the same.

The golden percentages

  • 68% within 1 SD: between μ - σ and μ + σ
  • 95% within 2 SDs: between μ - 2σ and μ + 2σ
  • 99.7% within 3 SDs: between μ - 3σ and μ + 3σ

Worked example

Heights: N(170, 10²). What % between 160 and 180 cm?

Step by step

  1. 160 = 170 - 10 = μ - σ. 180 = 170 + 10 = μ + σ
  2. Asking for percent within 1 SD of mean
  3. By the rule: 68%

Final answer

68% of people are 160-180 cm tall.

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Converting to the standard normal

To use z-tables and calculate exact probabilities, convert any normal distribution to standard normal: Z ~ N(0, 1) with mean 0 and SD 1.

z-score = how many SDs is X from the mean?
Interpreting z-scores: z = 0 means X = μ (at mean). z = 1 means 1 SD above. z = -2 means 2 SDs below. Positive z is above mean, negative z is below.

Worked example

X ~ N(100, 15²). Find z for x = 115 and x = 85.

Step by step

  1. For x = 115:
  2. For x = 85:
  3. Both exactly 1 SD away from mean.

Final answer

z(115) = 1, z(85) = -1.

Standard normal probabilities

The z-table gives Φ(z): Φ(z) = P(Z ≤ z) = area left of z. This is what z-tables show. Total area under curve = 1.

Using the z-table

  • Φ(z) = area to left of z
  • P(Z ≥ z) = 1 - Φ(z) (area to right)
  • P(Z ≤ -z) = 1 - Φ(z) by symmetry

Worked example: Find probability

Find P(Z ≤ 1.23) and P(Z > 1.23).

Step by step

  1. Look up z = 1.23 in table: Φ(1.23) = 0.8907
  2. P(Z > 1.23) = 1 - 0.8907 = 0.1093

Final answer

P(Z ≤ 1.23) = 89.07%. P(Z > 1.23) = 10.93%.

IB Exam Questions on Normal Distribution Properties

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How Normal Distribution Properties Appears in IB Exams

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Define

Give the precise meaning of key terms related to Normal Distribution Properties.

AO1
Describe

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AO2
Explain

Give reasons WHY — cause and effect within Normal Distribution Properties.

AO3
Evaluate

Weigh strengths AND limitations of approaches in Normal Distribution Properties.

AO3
Discuss

Present arguments FOR and AGAINST with a balanced conclusion.

AO3

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Related Math AI SL Topics

Continue learning with these related topics from the same unit:

4.1.1Population and Samples
4.1.2Data Classification
4.1.3Sampling Techniques
4.1.4Data Reliability and Outliers
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4.8.2Binomial Calculations
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Normal Probabilities4.9.2

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