Back to Topic 5.14 — Implicit & related rates (HL only)
5.14.3Math AA HL8 flashcards

Optimisation (HL contexts)

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Card 1 of 85.14.3
5.14.3
Question

What are the four steps of an optimisation problem?

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All 8 Flashcards — Optimisation (HL contexts)

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Card 1concept

Question

What are the four steps of an optimisation problem?

Answer

1) Write the quantity. 2) Reduce to one variable using the constraint. 3) Differentiate and set = 0. 4) Justify max/min and answer the question.

Card 2concept

Question

What condition holds at the optimum value?

Answer

The first derivative is zero (a stationary point).

Card 3concept

Question

How do you justify a stationary point is a maximum?

Answer

Second-derivative test: f″ < 0 ⇒ maximum (or f′ changes + to − through the point).

Card 4concept

Question

How do you justify a stationary point is a minimum?

Answer

f″ > 0 ⇒ minimum (or f′ changes − to + through the point).

Card 5concept

Question

Why minimise D² instead of D for a shortest-distance problem?

Answer

D² has the same minimising x as D (it's a monotone transformation) but avoids the messy square-root derivative.

Card 6formula

Question

Open box from an a×a sheet (corner squares x): volume formula?

Answer

V = x(a − 2x)², with domain 0 < x < a/2.

Card 7concept

Question

Why must you check the domain / reject some solutions?

Answer

Lengths can't be negative and some roots make a dimension zero — those are physically impossible.

Card 8concept

Question

After finding the optimum variable, what is often still required?

Answer

The optimum VALUE — substitute the variable back into the original quantity.

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