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Topic 3.11Math AA HL8 flashcards

Trig relationships (HL only)

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Card 1 of 83.11.1
3.11.1
Question

What is sec θ?

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All Flashcards in Topic 3.11

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3.11.18 cards

Card 1formula
Question

What is sec θ?

Answer

sec θ = 1/cos θ (the reciprocal of cosine).

Card 2formula
Question

What is csc θ (cosec θ)?

Answer

csc θ = 1/sin θ (the reciprocal of sine).

Card 3formula
Question

What is cot θ?

Answer

cot θ = 1/tan θ = cos θ / sin θ (the reciprocal of tangent).

Card 4formula
Question

State the three Pythagorean identities.

Answer

sin²θ + cos²θ = 1; 1 + tan²θ = sec²θ; 1 + cot²θ = csc²θ.

Card 5concept
Question

How do you derive 1 + tan²θ = sec²θ?

Answer

Divide sin²θ + cos²θ = 1 throughout by cos²θ.

Card 6concept
Question

How do you derive 1 + cot²θ = csc²θ?

Answer

Divide sin²θ + cos²θ = 1 throughout by sin²θ.

Card 7formula
Question

What is the co-function relationship sin(90° − θ)?

Answer

sin(90° − θ) = cos θ (and cos(90° − θ) = sin θ).

Card 8concept
Question

Best first step when a trig expression won't simplify?

Answer

Rewrite everything in sin and cos, combine over a common denominator, then use sin²+cos²=1.

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IB Math AA HL Topic 3.11 Flashcards | Trig relationships (HL only) | Aimnova | Aimnova