Unit 1: Structure 1: Models of the Particulate Nature of Matter

Topic 1.4: Counting Particles by Mass: The Mole Questions

Practice 20 exam-style questions for IB Chemistry Topic 1.4. Review the question stems below, then unlock the full Question Bank to access markschemes, model answers, and AI grading.

1Determine2 marks
A hydrocarbon has the empirical formula CH and a relative molecular mass of 78.

Determine its molecular formula.

(Empirical formula mass of CH = 13.02.) [2]
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2State1 mark
2026
State what is meant by the empirical formula of a compound.
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3State1 mark
2026
State the units of concentration when a solution is described in mol dm⁻³.
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4Calculate2 marks
A 5.85 g sample of sodium chloride, NaCl, is weighed out.

Calculate the amount, in moles, present.

(M(NaCl) = 58.44 g mol⁻¹.)
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5Draw1 mark
2026
Draw a diagram showing how the meniscus should be read in a volumetric flask.
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6Draw1 mark
2026
Draw a possible structural formula for this compound.
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7explain3 marks
Explain the difference between an empirical and a molecular formula, and state what extra information is needed to convert one into the other.
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8determine2 marks
A hydrocarbon has the empirical formula C₂H₅ and a relative molecular mass of 58. Determine its molecular formula.
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9determine3 marks
0.500 g of a metal oxide contains 0.400 g of the metal M, whose molar mass is 55.85 g mol⁻¹. Determine the empirical formula of the oxide.
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10calculate2 marks
Calculate the amount, in mol, represented by 3.01 × 10²³ atoms of carbon. (L = 6.02 × 10²³ mol⁻¹)
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11calculate2 marks
Calculate the mass of 0.250 mol of sodium chloride, NaCl. (M: Na 22.99, Cl 35.45)
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12calculate3 marks
Calculate the number of molecules in 10.0 g of carbon dioxide. (M(CO₂) = 44.01 g mol⁻¹, L = 6.02 × 10²³ mol⁻¹)
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13define3 marks
Define relative atomic mass and explain why the relative atomic mass of chlorine is 35.45 rather than a whole number.
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14calculate2 marks
Calculate the amount, in mol, of sodium chloride in 40.0 cm³ of a 0.250 mol dm⁻³ solution.
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15calculate3 marks
Calculate the mass, in g, of sodium chloride (M = 58.44 g mol⁻¹) needed to make 250 cm³ of a 0.150 mol dm⁻³ solution.
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16calculate2 marks
25.0 cm³ of 0.500 mol dm⁻³ hydrochloric acid is diluted with water to a total volume of 250.0 cm³. Calculate the concentration of the diluted solution.
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17outline3 marks
A student needs 500 cm³ of 0.100 mol dm⁻³ potassium nitrate solution. Outline the steps for preparing it accurately from the solid using a volumetric flask.
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18determine3 marks
A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen by mass. Determine its empirical formula. (M: C 12.01, H 1.01, O 16.00)
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19Calculate2 marks
Calculate the mass of glucose, C₆H₁₂O₆, needed to prepare 250.0 cm³ of a 0.100 mol dm⁻³ solution.

(M = 180.18 g mol⁻¹.) [2]
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20Calculate2 marks
A 25.0 cm³ sample of 0.480 mol dm⁻³ copper(II) sulfate solution is diluted with water to a total volume of 200.0 cm³.

Calculate the concentration of the diluted solution. [2]
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