Back to Topic 6.3 — Electron sharing reactions
6.3.2Chemistry12 flashcards

Nucleophilic substitution: SN1 and SN2 (HL)

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Card 1 of 126.3.2
6.3.2
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What is nucleophilic substitution?

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All 12 Flashcards — Nucleophilic substitution: SN1 and SN2 (HL)

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Card 1definition

Question

What is nucleophilic substitution?

Answer

A **nucleophile** replaces a **halide leaving group** on a halogenoalkane at the **δ+ carbon**: R–X + Nu⁻ → R–Nu + X⁻.

Card 2definition

Question

What is a nucleophile?

Answer

An **electron-pair donor** that attacks an electron-poor (δ+) atom; it has a **lone pair** (e.g. OH⁻, CN⁻, NH_{3}).

Card 3concept

Question

Why is the carbon in R–X δ+?

Answer

The halogen is more **electronegative** than carbon, so the polar C–halogen bond leaves the carbon partially positive (**δ+**).

Card 4process

Question

Describe the SN2 mechanism.

Answer

**One** concerted step: the nucleophile attacks the carbon from the **side opposite** the leaving group, via a **transition state** with partial bonds; configuration is **inverted**.

Card 5process

Question

Describe the SN1 mechanism.

Answer

**Two** steps: (1) slow **heterolysis** of C–halogen forms a **carbocation**; (2) fast attack of the nucleophile on the carbocation.

Card 6formula

Question

SN2 rate equation?

Answer

rate = k[halogenoalkane][Nu⁻] — **second** order (first order in each reactant).

Card 7formula

Question

SN1 rate equation?

Answer

rate = k[halogenoalkane] — **first** order; the nucleophile is **absent** (it joins in the fast step).

Card 8concept

Question

Which substrate favours SN2 and why?

Answer

**Primary** (1°): the carbon is **uncrowded**, so the nucleophile can reach it for back-side attack.

Card 9concept

Question

Which substrate favours SN1 and why?

Answer

**Tertiary** (3°): it forms a **stable tertiary carbocation** (alkyl groups spread the positive charge).

Card 10concept

Question

Why is a tertiary carbocation stable?

Answer

The three attached alkyl groups push electron density onto the positive carbon (**positive inductive effect**), spreading out the charge.

Card 11comparison

Question

Order of C–halogen reactivity in substitution?

Answer

**C–I > C–Br > C–Cl > C–F** — the weaker (longer) the bond, the better the leaving group, the faster the reaction.

Card 12concept

Question

Why does the iodoalkane react fastest?

Answer

The **C–I bond is the weakest**, so it breaks most easily and **iodide is the best leaving group**.

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