Back to Topic 5.3 — How far? The extent of chemical change
5.3.4Chemistry12 flashcards

Equilibrium calculations: Kc and ΔG (HL)

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Card 1 of 125.3.4
5.3.4
Question

How do you write the Kc expression?

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All 12 Flashcards — Equilibrium calculations: Kc and ΔG (HL)

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Card 1formula

Question

How do you write the Kc expression?

Answer

Products over reactants, each concentration raised to the power of its **stoichiometric coefficient**: $K_{c}=\dfrac{[\text{C}]^{c}[\text{D}]^{d}}{[\text{A}]^{a}[\text{B}]^{b}}$.

Card 2concept

Question

Which species are left OUT of Kc?

Answer

**Pure solids (s) and pure liquids (l)** — including the solvent in dilute solution — because their concentration is effectively constant.

Card 3concept

Question

What does a large Kc mean?

Answer

K_{c} ≫ 1 → equilibrium lies to the **right**: mostly **products** at equilibrium.

Card 4concept

Question

What does a small Kc mean?

Answer

K_{c} ≪ 1 → equilibrium lies to the **left**: mostly **reactants** at equilibrium.

Card 5concept

Question

What only affects the value of Kc?

Answer

**Temperature** only. Changing concentration, pressure or adding a catalyst does **not** change K_{c}.

Card 6definition

Question

What are the rows of an ICE table?

Answer

**I**nitial, **C**hange and **E**quilibrium amounts (or concentrations) for each species.

Card 7process

Question

How are the 'Change' values related?

Answer

They are in the **ratio of the stoichiometric coefficients** — reactants decrease (−), products increase (+).

Card 8definition

Question

What is the reaction quotient Q?

Answer

The **same expression as K_{c}**, but evaluated with the concentrations at **any moment**, not only at equilibrium.

Card 9concept

Question

Q < Kc — which way does the reaction shift?

Answer

**Forward** (→), making more product, until Q rises to K_{c}.

Card 10concept

Question

Q > Kc — which way does the reaction shift?

Answer

**Backward** (←), making more reactant, until Q falls to K_{c}.

Card 11formula

Question

What links ΔG° and K?

Answer

$\Delta G^{\circ}=-RT\ln K$ (given in the data booklet); R = 8.31 J K⁻¹ mol⁻¹, T in kelvin.

Card 12concept

Question

If K > 1, what is the sign of ΔG°?

Answer

ln K > 0, so ΔG° = −RT ln K is **negative** — the reaction is **spontaneous** and favours products.

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