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NotesMath AITopic 5.7
Unit 5 · Calculus · Topic 5.7

IB Math AI — Optimization

IB Mathematics AI SL topic covering core concepts and exam-style applications.

Exam technique guidePractice questions

Key concepts in Optimization

Key Idea: Optimisation is the real-world application of stationary points: finding the maximum profit, minimum cost, shortest time, or greatest area given a constraint. The technique is identical to Topic 5.6 — differentiate and set f'(x) = 0 — but now you must first build the function from a word problem, and interpret your answer with units in context.

✅ The 5-step optimisation method

Step 1: Define the variable
Choose one quantity as x. Be clear about what it represents and any constraints on its domain (e.g., x > 0, 0 < x < 10).
Step 2: Write the objective function
Express the quantity to maximise or minimise in terms of x. This is the function you will differentiate.
Step 3: Use the constraint
If there is a constraint (e.g., fixed perimeter, fixed volume), use it to eliminate one variable and express everything in terms of x.
Step 4: Differentiate and solve f'(x) = 0
Find the critical point. Solve the equation to get the x-value.
Step 5: Verify nature and interpret
Use f''(x) to confirm it is a max or min. Then find the actual maximum/minimum value and state it with units in context.
Example: A farmer has 100 m of fence to enclose a rectangular field with one side along a wall (no fence needed there). Maximise the area. Let x = width of the field. Then length = 100 − 2x. Area A = x(100 − 2x) = 100x − 2x² A'(x) = 100 − 4x = 0 → x = 25 m A''(x) = −4 < 0 → this is a maximum ✓ Length = 100 − 50 = 50 m. Maximum area = 25 × 50 = 1250 m²
Always check the domain after finding the critical x. An x that gives a negative length or area is outside the valid domain. If f''(x) = 0 at the critical point, test values either side of x to confirm max or min.
Paper 1 and 2: Show every step — setting up the function, differentiating, setting f'(x) = 0, verifying nature, and concluding in context. Marks are awarded at each stage. A correct final answer with no working earns few marks in extended questions. Context is essential: Don't just say 'x = 25' — say 'the width should be 25 m to achieve the maximum area of 1250 m²'.

IB-style question [5 marks]

A manufacturer's profit, in dollars, from selling x items is modelled by P(x) = 60x − x² − 200. Find the number of items that maximises the profit, and the maximum profit.

Step by step:

  1. Maximum profit occurs where the derivative is zero.

    P′(x)=60−2x=0⇒x=30P'(x) = 60 - 2x = 0 \Rightarrow x = 30P′(x)=60−2x=0⇒x=30
  2. Substitute x = 30 to find the maximum profit.

    P(30)=60(30)−302−200=1800−900−200=700P(30) = 60(30) - 30^2 - 200 = 1800 - 900 - 200 = 700P(30)=60(30)−302−200=1800−900−200=700
Final answer:

30 items gives the maximum profit of $700.

What you'll learn in Topic 5.7

  • 5.7.1 Optimisation in Context
Suggested study order: Read the notes for each sub-topic below → test yourself with flashcards → attempt practice questions → review exam technique.

Study resources — 5.7 Optimization

5.7.1

Optimisation in Context

Notes

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Topic 5.7 Optimization forms a core part of Unit 5: Calculus in IB Math AI. Mastering these concepts will strengthen your understanding of connected topics across the syllabus and prepare you for exam questions that require analysis, evaluation, and real-world application.

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