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v0.1.1298
NotesMath AITopic 2.4
Unit 2 · Functions · Topic 2.4

IB Math AI — Features of a graph

IB Mathematics AI SL topic covering core concepts and exam-style applications.

Exam technique guidePractice questions

Key concepts in Features of a graph

Key Idea: Topic 2.4 is about describing the shape and behaviour of a graph: where it rises, where it falls, where it peaks or troughs, and how it behaves at its extremes. A local maximum is a peak — the function is higher there than at nearby points. A local minimum is a trough. An asymptote is a line the graph approaches but never reaches.

✅ Graph features and what they tell you

Example: Describe f(x) = x³ − 3x: GDC shows: local max at (−1, 2), local min at (1, −2). Increasing on: x < −1 and x > 1. Decreasing on: −1 < x < 1. Exponential: f(x) = 3⁻ˣ + 1: As x → ∞, 3⁻ˣ → 0, so f(x) → 1. Horizontal asymptote: y = 1 (the graph gets closer and closer but never reaches 1).
When describing increasing/decreasing intervals, use the x-values (not y-values) for the interval. A function can have more than one local maximum or minimum — use the GDC to find all of them within the domain shown.
Paper 2 (GDC allowed): Use the GDC 'maximum' and 'minimum' functions to find turning point coordinates. Then state the intervals of increase/decrease around those points. Paper 1: You may be given a sketch and asked to describe features in words. Use precise vocabulary: 'local maximum at x = 2, f(2) = 5', not just 'it goes up then down'.

IB-style question [6 marks]

The number of active users of an app, N thousand, t months after a redesign is modelled by N(t) = 400 · 0.7ᵗ + 60, for t ≥ 0. (a) Write down the number of active users at the moment of the redesign (t = 0). (b) State whether N is increasing or decreasing, and explain why. (c) Write down the equation of the horizontal asymptote and interpret it in context.

Step by step:

  1. (a) Substitute t = 0. Since 0.7⁰ = 1, the model gives the starting value.

    N(0)=400×1+60=460 thousand usersN(0) = 400 \times 1 + 60 = 460 \text{ thousand users}N(0)=400×1+60=460 thousand users
  2. (b) The base 0.7 is between 0 and 1, so the term 400 · 0.7ᵗ shrinks as t grows. The output falls over time, so N is decreasing.

  3. (c) As t → ∞, the term 400 · 0.7ᵗ → 0, leaving the constant.

    N→60  ⇒  horizontal asymptote N=60N \to 60 \;\Rightarrow\; \text{horizontal asymptote } N = 60N→60⇒horizontal asymptote N=60
  4. Interpret it: in the long run the user base levels off at about 60 thousand active users — the model never drops below this floor.

Final answer:

(a) 460 thousand users. (b) Decreasing — the base 0.7 < 1 makes the curve fall. (c) N = 60; the user base settles at about 60 thousand in the long run.

What you'll learn in Topic 2.4

  • 2.4.1 Local maxima and minima
  • 2.4.2 Increasing and decreasing intervals
  • 2.4.3 Asymptotes and graph behaviour
Suggested study order: Read the notes for each sub-topic below → test yourself with flashcards → attempt practice questions → review exam technique.

Study resources — 2.4 Features of a graph

2.4.1

Local maxima and minima

Notes
2.4.2

Increasing and decreasing intervals

Notes
2.4.3

Asymptotes and graph behaviour

Notes

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Topic 2.4 Features of a graph forms a core part of Unit 2: Functions in IB Math AI. Mastering these concepts will strengthen your understanding of connected topics across the syllabus and prepare you for exam questions that require analysis, evaluation, and real-world application.

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