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NotesMath AI HLTopic 3.5Perpendicular Bisectors
Back to Math AI HL Topics
3.5.23 min read

Perpendicular Bisectors (Math AI HL)

IB Mathematics: Applications and Interpretation • Unit 3

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Contents

  • What is a perpendicular bisector?
  • Finding the equation — step by step
  • Perpendicular gradient rule
  • IB exam-style problems
Two properties in one line: The perpendicular bisector of segment AB: (1) passes through the midpoint of AB, and (2) is perpendicular to AB.

Every point on the bisector is equidistant from A and B.

Interactive: switch to ''Perpendicular Bisector'' tab to see the bisector through midpoint M.

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Connection to Voronoi: In a Voronoi diagram, the boundary between two cells is the perpendicular bisector of the two sites.

This is why perpendicular bisectors are foundational to 3.6.

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Three-step method: Step 1: Find the midpoint M.

Step 2: Find the gradient of AB, then take the negative reciprocal for the perpendicular gradient.

Step 3: Use y − y₁ = m(x − x₁) with M as the point.

Worked example

Find the equation of the perpendicular bisector of AB where A = (1, 3) and B = (5, 7).

Step by step

  1. Step 1: Midpoint M.
  2. Step 2: Gradient of AB.
  3. Perpendicular gradient (negative reciprocal).
  4. Step 3: Equation through M(3, 5) with m = −1.

Final answer

Perpendicular bisector: y = −x + 8.

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Perpendicular gradients multiply to −1: If two lines are perpendicular, their gradients m₁ and m₂ satisfy: m₁ × m₂ = −1.

So if AB has gradient 3, the perpendicular has gradient −1/3.
Gradient of ABPerpendicular gradient
2−1/2
−31/3
1/4−4
0 (horizontal)Undefined (vertical line)
Zero gradient special case: If AB is horizontal (gradient 0), the perpendicular bisector is a vertical line x = midpoint x-value.

Worked example — verify a point lies on the bisector

The perpendicular bisector of PQ, where P = (2, 4) and Q = (6, 2), passes through the point (4, 6).

Verify this.

Step by step

  1. Find bisector equation. Midpoint: M = (4, 3). Gradient PQ = (2−4)/(6−2) = −1/2. Perpendicular gradient = 2.
  2. Equation: y − 3 = 2(x − 4) → y = 2x − 5.
  3. Check (4, 6): y = 2(4) − 5 = 3 ≠ 6.

Final answer

The point (4, 6) does NOT lie on the bisector (y = 2x − 5 gives y = 3 at x = 4, not 6).

IB-style question — equidistant point on a road

Two shops are at A(2, 1) and B(8, 5). A new café must be the same distance from both shops and must lie on the road y = x − 1.

Find the coordinates of the café.

Step by step

  1. 'Same distance from A and B' means the café is on the perpendicular bisector of [AB]. Midpoint and gradient first.
  2. Equation of the perpendicular bisector through M.
  3. It must also be on the road, so set the two lines equal and solve.

Final answer

The café is at (4.6, 3.6).

The café lies on the perpendicular bisector of [AB] (equal distance from both shops) AND on the road — so it's where those two lines cross.

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in words why every point on the perpendicular bisector of [AB] is equidistant from A and B. [2 marks]

Related Math AI HL Topics

Continue learning with these related topics from the same unit:

3.1.1Distance & midpoint in 2D
3.1.2Distance & midpoint in 3D
3.1.3Volume and Surface Area of 3D Solids
3.10.1Vector definitions
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