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c059741
NotesMath AA HLTopic 1.7
Unit 1 · Number & Algebra · Topic 1.7

IB Math AA HL — Exponent & log laws

Topic 1.7 of IB Mathematics: Analysis and Approaches covers Exponent & log laws, which is part of Unit 1: Number & Algebra. Students explore key concepts including Laws of exponents, Laws of logarithms, Exponential & log equations. A strong understanding of exponent & log laws is essential for IB Math AA HL exams and builds the foundation for connected topics across the syllabus.

Higher Level students should use this topic hub as a map: start with the shared sub-topics, then follow the HL-only extensions and exam-skill links where this topic asks for deeper analysis.

Exam technique guidePractice questions

Key concepts in Exponent & log laws

Key Idea: These are your algebra cheat-sheets for powers and logs — used to simplify expressions and to solve exponential and log equations. Almost all of it is Paper 1 by hand; Paper 2 only adds a graphing shortcut.

⚡ Laws of exponents (Paper 1)

aman=am+n,aman=am−n,(am)n=amna^m a^n = a^{m+n}, \quad \frac{a^m}{a^n} = a^{m-n}, \quad (a^m)^n = a^{mn}aman=am+n,anam​=am−n,(am)n=amn
aaa
the common base — must be the same to combine
a−n=1ana^{-n} = \tfrac{1}{a^n}a−n=an1​
negative power = reciprocal
am/n=(an)ma^{m/n} = (\sqrt[n]{a})^{m}am/n=(na​)m
fractional power = nth root, then mth power
OperationRule (same base)Example
MultiplyAdd the exponentsx⁵ × x³ = x⁸
DivideSubtract the exponentsx⁸ ÷ x² = x⁶
Power of a powerMultiply the exponents(x²)³ = x⁶
Power 0Always 1a⁰ = 1
FractionalRoot (bottom), then power (top)27²/³ = (∛27)² = 9

🟰 Laws of logarithms (Paper 1)

log⁡axy=log⁡ax+log⁡ay,log⁡axy=log⁡ax−log⁡ay,log⁡axm=mlog⁡ax,log⁡ax=log⁡bxlog⁡ba\log_a xy = \log_a x + \log_a y, \quad \log_a \tfrac{x}{y} = \log_a x - \log_a y, \quad \log_a x^m = m\log_a x, \quad \log_a x = \frac{\log_b x}{\log_b a}loga​xy=loga​x+loga​y,loga​yx​=loga​x−loga​y,loga​xm=mloga​x,loga​x=logb​alogb​x​
log⁡a1=0\log_a 1 = 0loga​1=0
log of 1 is always 0
log⁡aa=1\log_a a = 1loga​a=1
log of the base is 1
log⁡bxlog⁡ba\frac{\log_b x}{\log_b a}logb​alogb​x​
change of base — swap to any base you can compute
LawCombine (→)Expand (←)
Productlog x + log y = log(xy)Split a product into a sum
Quotientlog x − log y = log(x/y)Split a quotient into a difference
Powerm log x = log xᵐBring an exponent down as a coefficient
Change of baselogₐ x = log x ÷ log aRewrite an awkward base
Equation typeMethodQuick example
aˣ = b, bases matchEquate the exponents4ˣ = 8 → 2²ˣ = 2³ → x = 3/2
aˣ = b, bases differTake logs (power law drops x)5ˣ = 20 → x = log 20 / log 5
logₐ(expr) = cConvert: expr = aᶜln(x²−16) = 0 → x² − 16 = 1
Two logs = cCombine to one log, then convertlog₂x + log₂(x−2) = 3 → x = 4

✏️ IB-style worked examples

IB-style question — simplify with the index laws

Simplify (p⁵ × p³) ÷ p², leaving your answer as a single power of p.

Step by step:

  1. Multiply — add the exponents.

    p5×p3=p5+3=p8p^5 \times p^3 = p^{5+3} = p^8p5×p3=p5+3=p8
  2. Divide — subtract the exponent.

    p8p2=p8−2=p6\frac{p^8}{p^2} = p^{8-2} = p^6p2p8​=p8−2=p6
Final answer:

p⁶

IB-style question — condense into a single logarithm

Write ln 5 + 2 ln 2 − ln 10 as a single logarithm.

Step by step:

  1. Coefficient first: the power law moves the 2 up.

    2ln⁡2=ln⁡22=ln⁡42\ln 2 = \ln 2^2 = \ln 42ln2=ln22=ln4
  2. Add → multiply on top, subtract → divide.

    ln⁡5+ln⁡4−ln⁡10=ln⁡5×410\ln 5 + \ln 4 - \ln 10 = \ln \frac{5 \times 4}{10}ln5+ln4−ln10=ln105×4​
  3. Simplify the inside.

    =ln⁡2= \ln 2=ln2
Final answer:

ln 2

IB-style question — solve an exponential by taking logs

Solve 7ˣ = 50, giving the exact value of x.

Step by step:

  1. Bases won't match, so take logs of both sides.

    log⁡7x=log⁡50\log 7^x = \log 50log7x=log50
  2. The power law brings x down.

    xlog⁡7=log⁡50x \log 7 = \log 50xlog7=log50
  3. Divide to isolate x.

    x=log⁡50log⁡7≈2.01x = \frac{\log 50}{\log 7} \approx 2.01x=log7log50​≈2.01
Final answer:

x = log 50 / log 7 (≈ 2.01)

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Important: log(x + y) ≠ log x + log y. The laws act only on a product, quotient or power — never on a sum or difference inside one log. And after solving a log equation, check every argument is positive: discard any root that makes a log's inside ≤ 0.

Tap each card to reveal the answer.

Simplify x⁷ ÷ x³ x⁴ — divide means subtract the exponents, 7 − 3.

Evaluate 16³/⁴ without a calculator 8 — fourth root of 16 is 2, then 2³ = 8.

Write 2 log x + log y as one logarithm log(x²y) — the 2 becomes a power, then add → multiply.

Solve 2ˣ = 16 x = 4 — write 16 = 2⁴, equal bases ⇒ equal exponents.

Solve ln x = 3, exact answer x = e³ — convert to exponential form: x = e³.

Exam Tips

  • Same base only: multiply → add exponents, divide → subtract, power of a power → multiply.
  • Negative power = reciprocal; fractional power m/n = nth root then mth power.
  • Logs: product → add, quotient → subtract, power → coefficient (read right-to-left to combine).
  • Bases match → equate exponents; otherwise take logs. A lone log = number → convert to expr = aᶜ.
  • Reject any solution that makes a log's argument ≤ 0, and use change of base for an awkward base.

What you'll learn in Topic 1.7

  • 1.7.1 Laws of exponents
  • 1.7.2 Laws of logarithms
  • 1.7.3 Exponential & log equations
Suggested study order: Read the notes for each sub-topic below → test yourself with flashcards → attempt practice questions → review exam technique.

Study resources — 1.7 Exponent & log laws

1.7.1

Laws of exponents

Notes
1.7.2

Laws of logarithms

Notes
1.7.3

Exponential & log equations

Notes

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Topic 1.7 Exponent & log laws forms a core part of Unit 1: Number & Algebra in IB Math AA HL. Mastering these concepts will strengthen your understanding of connected topics across the syllabus and prepare you for exam questions that require analysis, evaluation, and real-world application.

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